In [1]:
%pylab inline
At a location in Europe, it is necessary to supply 1000 kW of 60-Hz power. The only power sources available operate at 50 Hz. It is decided to generate the power by means of a motor-generator set consisting of a synchronous motor driving a synchronous generator.
In [2]:
fse1 = 50.0 # [Hz]
fse2 = 60.0 # [Hz]
The speed of a synchronous machine is related to its frequency by the equation:
$$f_{se} = \frac{n_{sm}\cdot p/2}{60}$$To make a 50 Hz and a 60 Hz machine have the same mechanical speed so that they can be coupled together, we see that:
$$n_\text{sync} = \frac{120f_{se,1}}{p_1} = \frac{120f_{se,2}}{p_2}$$
In [3]:
p2_p1 = (120*fse2) / (120*fse1)
print('p2_p1 = {:.2f}'.format(p2_p1))
Therefore, a 10-pole synchronous motor must be coupled to a 12-pole synchronous generator to accomplish this frequency conversion.