In [1]:
%pylab inline
A 10-kVA 480/120-V conventional transformer is to be used to supply power from a 600-V source to a 480-V load. Consider the transformer to be ideal, and assume that all insulation can handle 600 V.
In [2]:
Sw = 10e3 # [VA]
Vp = 600 # [V]
Vh = 480 # [V] which is also the load voltage
Vl = 120 # [V]
The transformer in Problem 2-18 is identical to the transformer in Problem 2-17, but there is a significant difference in the apparent power capability of the transformer in the two situations.
In [3]:
n = Vh/Vl # = Nc/Nse
n
Out[3]:
In [4]:
Sio = (1 + n)/1 * Sw
print('''
Sio = {:.1f} kVA
==============
'''.format(Sio/1000))
In [5]:
Ip = Sio/Vp
print('''
Ip = {:.1f} A
===========
'''.format(Ip))
and the maximum secondary current is:
$$I_S = \frac{S}{V_S}$$
In [6]:
Is = Sio/Vh
print('''
s = {:.0f} A
=========
'''.format(Is))