Project Euler: Problem 6

The sum of the squares of the first ten natural numbers is,

$$1^2 + 2^2 + ... + 10^2 = 385$$

The square of the sum of the first ten natural numbers is,

$$(1 + 2 + ... + 10)^2 = 552 = 3025$$

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.



In [4]:

    
x=[]
y=[]
for i in range(101):
    x.append(i**2)
    y.append(i)
f=sum(x)
g=sum(y)**2
print(g-f)
raise NotImplementedError()









    



25164150






    



---------------------------------------------------------------------------
NotImplementedError                       Traceback (most recent call last)
<ipython-input-4-96ed9bfbb11b> in <module>()
      7 g=sum(y)**2
      8 print(g-f)
----> 9 raise NotImplementedError()

NotImplementedError:



In [ ]:

    
# This cell will be used for grading, leave it at the end of the notebook.