Project Euler: Problem 6

https://projecteuler.net/problem=6

The sum of the squares of the first ten natural numbers is,

$$1^2 + 2^2 + ... + 10^2 = 385$$

The square of the sum of the first ten natural numbers is,

$$(1 + 2 + ... + 10)^2 = 552 = 3025$$

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

I used list comprehension to create the necessary lists, then subtracted those lists to find the answer.


In [10]:
SumOfSquares = sum(i**2 for i in range(1,101))
SquareOfSum = (sum(i for i in range(1,101)))**2
print("Answer: " + str(SquareOfSum - SumOfSquares))


Answer: 25164150

In [ ]:
# This cell will be used for grading, leave it at the end of the notebook.