Project Euler: Problem 6

The sum of the squares of the first ten natural numbers is,

$$1^2 + 2^2 + ... + 10^2 = 385$$

The square of the sum of the first ten natural numbers is,

$$(1 + 2 + ... + 10)^2 = 552 = 3025$$

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.



In [24]:

    
#create a function to compute the sum of squares
def sum_of_squares(limit):
    #assign variables
    total = 0
    answer = range(0,limit+1)
    #as answer variable creates list, create a running sum of each number squared
    for number in answer:
        total += number**2
    return total

#create a function to create the square of sum
def square_of_sum(limit):
    #assign variables
    answer = range(0,limit+1)
    total = sum(answer)
    #return the square of the running sum
    return total**2
print (square_of_sum(10) - sum_of_squares(10))



In [21]:

    
# This cell will be used for grading, leave it at the end of the notebook.