Project Euler: Problem 6

The sum of the squares of the first ten natural numbers is,

$$1^2 + 2^2 + ... + 10^2 = 385$$

The square of the sum of the first ten natural numbers is,

$$(1 + 2 + ... + 10)^2 = 552 = 3025$$

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.



In [4]:

    
def sum_of_squares(num):
    summ = 0
    for i in range(1,num+1):
        summ += i**2
    return summ



In [5]:

    
def square_of_sum(num):
    square = 0
    for i in range(1,num+1):
        square += i
    return square**2



In [8]:

    
def difference(num):
    return square_of_sum(num) - sum_of_squares(num)

print(difference(100))

25164150



In [ ]:

    
# This cell will be used for grading, leave it at the end of the notebook.