Project Euler: Problem 6

The sum of the squares of the first ten natural numbers is,

$$1^2 + 2^2 + ... + 10^2 = 385$$

The square of the sum of the first ten natural numbers is,

$$(1 + 2 + ... + 10)^2 = 552 = 3025$$

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.



In [13]:

    
def sum_squares_first100():
    total = 0
    x = 1
    while x in range(1, 101):
        total = total + x**2
        x += 1
    return total
print(sum_squares_first100())



In [14]:

    
def comparison_sums(a, b):
    return a - b



In [18]:

    
c = sum_squares_first100()**2
d =sum_squares_first100()
print(comparison_sums(c, d))

114480384150



In [16]:

    
# This cell will be used for grading, leave it at the end of the notebook.



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