https://projecteuler.net/problem=6
The sum of the squares of the first ten natural numbers is,
$$1^2 + 2^2 + ... + 10^2 = 385$$The square of the sum of the first ten natural numbers is,
$$(1 + 2 + ... + 10)^2 = 552 = 3025$$Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
In [8]:
# YOUR CODE HERE
one_hundred = [i for i in range(1,101)]
square_hundred = [i**2 for i in range(1, 101)]
sum_square = sum(one_hundred)
square_sum = sum(square_hundred)
print(sum_square**2)
print(square_sum)
diff = (sum_square**2) - square_sum
print(diff)
In [ ]:
# This cell will be used for grading, leave it at the end of the notebook.