Project Euler: Problem 6

The sum of the squares of the first ten natural numbers is,

$$1^2 + 2^2 + ... + 10^2 = 385$$

The square of the sum of the first ten natural numbers is,

$$(1 + 2 + ... + 10)^2 = 552 = 3025$$

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.



In [1]:

    
#Pretty simple process.  I summed all the y's up and squared the sum and then I subtracted each x^2 (1-100) from that result.
x = 0
y = 0
n = 0
while (y < 100):
    y = y + 1
    n = n + y
#print (y)
#print (n)
n = (n ** 2)
while (x < 100):
    x = x + 1
    n = n - (x ** 2)
#print (x)
print (n)
#raise NotImplementedError()

25164150



In [ ]:

    
# This cell will be used for grading, leave it at the end of the notebook.