Project Euler: Problem 6

The sum of the squares of the first ten natural numbers is,

$$1^2 + 2^2 + ... + 10^2 = 385$$

The square of the sum of the first ten natural numbers is,

$$(1 + 2 + ... + 10)^2 = 552 = 3025$$

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.



In [1]:

    
square=0 
for i in range(101):
    square=square+i**2 #sums the squares of the first 100 natural numbers
n=[]
for x in range(101):
    n.append(x) #makes a list of the first 100 natural numbers 
print(sum(n)**2-square) #finds the difference of the square of the sum and sum of the squares

25164150



In [ ]:

    
# This cell will be used for grading, leave it at the end of the notebook.