https://projecteuler.net/problem=6
The sum of the squares of the first ten natural numbers is,
$$1^2 + 2^2 + ... + 10^2 = 385$$The square of the sum of the first ten natural numbers is,
$$(1 + 2 + ... + 10)^2 = 552 = 3025$$Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
In [13]:
# YOUR CODE HERE
x=0
y=0
z=0
w=0
for i in range(100):
number =(i+1)**2
x=x + number
y=y+ (i+1)
z=y**2
w=z-x
print (w)
In [ ]:
# This cell will be used for grading, leave it at the end of the notebook.