https://projecteuler.net/problem=6

The sum of the squares of the first ten natural numbers is,

$$1^2 + 2^2 + ... + 10^2 = 385$$The square of the sum of the first ten natural numbers is,

$$(1 + 2 + ... + 10)^2 = 552 = 3025$$Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

```
In [1]:
```sumofsquare = sum([x**2 for x in range(1,101)])
squareofsum = sum([x for x in range(1,101)])**2
diff = squareofsum-sumofsquare
print(diff)

```
```

```
In [ ]:
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