Project Euler: Problem 6

https://projecteuler.net/problem=6

The sum of the squares of the first ten natural numbers is,

$$1^2 + 2^2 + ... + 10^2 = 385$$

The square of the sum of the first ten natural numbers is,

$$(1 + 2 + ... + 10)^2 = 552 = 3025$$

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.


In [1]:
sumofsquare = sum([x**2 for x in range(1,101)])
squareofsum = sum([x for x in range(1,101)])**2
diff = squareofsum-sumofsquare
print(diff)


25164150

In [ ]:
# This cell will be used for grading, leave it at the end of the notebook.