In [1]:
MSGS = [
"315c4eeaa8b5f8aaf9174145bf43e1784b8fa00dc71d885a804e5ee9fa40b16349c146fb778cdf2d3aff021dfff5b403b510d0d0455468aeb98622b137dae857553ccd8883a7bc37520e06e515d22c954eba5025b8cc57ee59418ce7dc6bc41556bdb36bbca3e8774301fbcaa3b83b220809560987815f65286764703de0f3d524400a19b159610b11ef3e",
"234c02ecbbfbafa3ed18510abd11fa724fcda2018a1a8342cf064bbde548b12b07df44ba7191d9606ef4081ffde5ad46a5069d9f7f543bedb9c861bf29c7e205132eda9382b0bc2c5c4b45f919cf3a9f1cb74151f6d551f4480c82b2cb24cc5b028aa76eb7b4ab24171ab3cdadb8356f",
"32510ba9a7b2bba9b8005d43a304b5714cc0bb0c8a34884dd91304b8ad40b62b07df44ba6e9d8a2368e51d04e0e7b207b70b9b8261112bacb6c866a232dfe257527dc29398f5f3251a0d47e503c66e935de81230b59b7afb5f41afa8d661cb",
"32510ba9aab2a8a4fd06414fb517b5605cc0aa0dc91a8908c2064ba8ad5ea06a029056f47a8ad3306ef5021eafe1ac01a81197847a5c68a1b78769a37bc8f4575432c198ccb4ef63590256e305cd3a9544ee4160ead45aef520489e7da7d835402bca670bda8eb775200b8dabbba246b130f040d8ec6447e2c767f3d30ed81ea2e4c1404e1315a1010e7229be6636aaa",
"3f561ba9adb4b6ebec54424ba317b564418fac0dd35f8c08d31a1fe9e24fe56808c213f17c81d9607cee021dafe1e001b21ade877a5e68bea88d61b93ac5ee0d562e8e9582f5ef375f0a4ae20ed86e935de81230b59b73fb4302cd95d770c65b40aaa065f2a5e33a5a0bb5dcaba43722130f042f8ec85b7c2070",
"32510bfbacfbb9befd54415da243e1695ecabd58c519cd4bd2061bbde24eb76a19d84aba34d8de287be84d07e7e9a30ee714979c7e1123a8bd9822a33ecaf512472e8e8f8db3f9635c1949e640c621854eba0d79eccf52ff111284b4cc61d11902aebc66f2b2e436434eacc0aba938220b084800c2ca4e693522643573b2c4ce35050b0cf774201f0fe52ac9f26d71b6cf61a711cc229f77ace7aa88a2f19983122b11be87a59c355d25f8e4",
"32510bfbacfbb9befd54415da243e1695ecabd58c519cd4bd90f1fa6ea5ba47b01c909ba7696cf606ef40c04afe1ac0aa8148dd066592ded9f8774b529c7ea125d298e8883f5e9305f4b44f915cb2bd05af51373fd9b4af511039fa2d96f83414aaaf261bda2e97b170fb5cce2a53e675c154c0d9681596934777e2275b381ce2e40582afe67650b13e72287ff2270abcf73bb028932836fbdecfecee0a3b894473c1bbeb6b4913a536ce4f9b13f1efff71ea313c8661dd9a4ce",
"315c4eeaa8b5f8bffd11155ea506b56041c6a00c8a08854dd21a4bbde54ce56801d943ba708b8a3574f40c00fff9e00fa1439fd0654327a3bfc860b92f89ee04132ecb9298f5fd2d5e4b45e40ecc3b9d59e9417df7c95bba410e9aa2ca24c5474da2f276baa3ac325918b2daada43d6712150441c2e04f6565517f317da9d3",
"271946f9bbb2aeadec111841a81abc300ecaa01bd8069d5cc91005e9fe4aad6e04d513e96d99de2569bc5e50eeeca709b50a8a987f4264edb6896fb537d0a716132ddc938fb0f836480e06ed0fcd6e9759f40462f9cf57f4564186a2c1778f1543efa270bda5e933421cbe88a4a52222190f471e9bd15f652b653b7071aec59a2705081ffe72651d08f822c9ed6d76e48b63ab15d0208573a7eef027",
"466d06ece998b7a2fb1d464fed2ced7641ddaa3cc31c9941cf110abbf409ed39598005b3399ccfafb61d0315fca0a314be138a9f32503bedac8067f03adbf3575c3b8edc9ba7f537530541ab0f9f3cd04ff50d66f1d559ba520e89a2cb2a83"
]
DE = "32510ba9babebbbefd001547a810e67149caee11d945cd7fc81a05e9f85aac650e9052ba6a8cd8257bf14d13e6f0a803b54fde9e77472dbff89d71b57bddef121336cb85ccb8f3315f4b52e301d16e9f52f904"
In [2]:
import sys
def strxor(a, b): # xor two strings of different lengths
#a = bytearray(a)
#b = bytearray(b)
if len(a) > len(b):
return "".join([chr(ord(x) ^ ord(y)) for (x, y) in zip(a[:len(b)], b)])
#return "".join([chr(x ^ y) for (x, y) in zip(a[:len(b)], b)])
'''
chr() return the string representing a character whose Unicode code point is the integer i.
ord() Given a string representing one Unicode character, return an integer representing the Unicode code point of that character.
'''
else:
return "".join([chr(ord(x) ^ ord(y)) for (x, y) in zip(a, b[:len(a)])])
#return "".join([chr(x ^ y) for (x, y) in zip(a, b[:len(a)])])
def random(size=16):
return open("/dev/urandom",encoding = "ISO-8859-1").read(size)
def encrypt(key, msg):
c = strxor(key, msg)
print
#print (c.encode('hex'))
#print(c.encode("ISO-8859-1"))
#print (codecs.encode(c, "ISO-8859-1"))
return c
def main():
key = random(1024)
ciphertexts = [(key, msg) for msg in MSGS]
In [3]:
#" " ascii = 0010 0000
a = "afdsfasdi"
b = " h f g "
print("a ^ b = ",strxor(b,a),"\n")
print("a ^ b ^ b = ",strxor(strxor(b,a),b))
In [4]:
m1 = " I am a boy"
m2 = "You are pig"
key = random(1024)
c1 = encrypt(key,m1)
c2 = encrypt(key,m2)
c1
c2
encrypt(c1,c2)
Out[4]:
In [5]:
import codecs
M = [" "]*len(MSGS)
for i in range(len(MSGS)):
M[i] = [str(chr(k)) for k in codecs.decode(MSGS[i],'hex')]
In [6]:
ciphertexts = [encrypt(M[6], msg) for msg in M]
l = len(ciphertexts)
guess = []*len(ciphertexts)
for m in range(l):
ll = len(ciphertexts[m])
gu = []
for i in range(ll):
if(ciphertexts[m][i].isalpha()):
gu.append(ciphertexts[m][i])
#guess.insert(i,ciphertexts[m][i])
#guess[i] = ciphertexts[m][i]
else:
gu.append("_")
#guess.remove(i)
#guess.insert(i," ")
#if(~guess[i].isalpha()):
#guess[i] = " "
guess.append(gu)
six = []
for le in range(len(guess[6])):
temp = []
for i in guess:
if(len(i)> le):
if( (i[le].isalpha())):
temp.append(i[le])
temp.sort()
print(temp)
if len(temp) > 1:
tt = 0
maxx = 0
for m in range(len(temp)):
if m==0:
ttext = temp[m]
tt = 1
maxx = 1
else:
if temp[m] == temp[m-1]:
tt = tt + 1
if(tt > maxx):
ttext = temp[m]
maxx = tt
else:
tt = 1
six.append(ttext)
elif len(temp) ==1 :
six.append(temp[0])
else:
six.append("_")
print(six)
In [7]:
import codecs
n6 = codecs.decode(MSGS[6],'hex')
n60 = []
n60 = n60 + [str(chr(i)) for i in codecs.decode(MSGS[6],'hex')]
crib ="There are two types of cyptography: one that allows the Government to use brute force "
key = encrypt(n60,crib)
n9 = codecs.decode(DE,'hex')
n90 = []
n90 = n90 + [str(chr(i)) for i in n9]
encrypt(key,n90)
Out[7]:
In [8]:
a = 80
a = a+1
str(chr(a))
Out[8]: