automaton.has_bounded_lag

Check if the transducer has bounded lag, i.e. that the difference of length between the input and output words is bounded, for every word accepted.

It is a pre-condition for transducer synchronization.

Preconditions:

The automaton has at least 2 tapes

Examples



In [1]:

    
import vcsn
ctx = vcsn.context("lat<lan_char(ab), lan_char(xy)>, b")
ctx









    



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    Out[1]:





$(\{a, b\})^? \times (\{x, y\})^?\rightarrow\mathbb{B}$



In [2]:

    
a = ctx.expression(r"'a,x''b,y'*'a,\e'").automaton()
a









    Out[2]:

This automaton has a bounded lag: there is at most a difference of 1 between the length of the input and the length of the output (e.g., $abba \rightarrow xyy$).



In [3]:

    
a.has_bounded_lag()









    Out[3]:





True



In [4]:

    
b = ctx.expression(r"(\e|x)(a|\e)*(b|y)").automaton()
b









    Out[4]:

This transducer, however, doesn't have a bounded lag: there can be an arbitrary large difference between the input and output. For example, $ab \rightarrow xy$, but $aaaaaaaaab \rightarrow xy$.



In [5]:

    
b.has_bounded_lag()









    Out[5]:





False



In [6]:

    
ctx_3 = vcsn.context("lat<lan_char(ab), lan_char(jk), lan_char(xy)>, b")
c = ctx_3.expression(r"(a|j|x)(b|k|\e)*").automaton()
c









    Out[6]:

In the case of more than 2 tapes, has_bounded_lag checks that every tape has a bounded lag compared to the first one (incidentally, if that is the case, it will insure that every tapes has a bounded lag in respect to every other). This transducer has a bounded lag if you only consider the first 2 tapes, but the third tape doesn't.



In [7]:

    
c.has_bounded_lag()









    Out[7]:





False