Parse the following dates and sort them by first 'date' then 'index' (== original position) and return a Series in the following form:
23 1971-07-08
19 2008-06-01
7 2009-01-01
21 2009-01-01
16 2009-02-01
4 2009-03-20
5 2009-03-20
6 2009-03-20
9 2009-03-20
10 2009-03-20
11 2009-03-20
12 2009-03-20
13 2009-03-20
14 2009-03-21
15 2009-03-22
0 2009-04-20
1 2009-04-20
17 2009-09-01
20 2009-12-01
22 2010-01-01
18 2010-10-01
3 2011-04-03
2 2014-04-20
8 2017-03-20
Name: dt, dtype: datetime64[ns]
Hints:
pd.to_datetime()
In [1]:
import pandas as pd
time_values = '''I come at 04/20/2009 ...; 04/20/09 in Bremen; 4/20/14 maybe; or 4/3/2011 also possible;
never at Mar-20-2009, but maybe later; how about Mar 20, 2009 or not; Moskow: March 20, 2009, 12:00;
in Koeln, Mar. 20, 2009 however; Why not Mar 20 2017 ?; Clear picture for 20 Mar 2009; In the iden of 20 March 2009;
20 Mar. 2009 in Dresden; 20 March, 2009 BR; Mar 20th, 2009 Hamburg; Current date: Mar 21st, 2009;
Mar 22nd is spring, 2009 Kiel; Feb 2009 is winter; Sep 2009; long ago in Oct 2010; 6/2008 vacation in Schwerin; 12/2009 blackout; 2009 timeout; Year 2010 the rest is history;
Soccer game at 7/8/71 in NY'''
time_s = pd.Series(time_values.split(';')).str.strip()
time_s
Out[1]:
In [2]:
def date_sorter(df):
# TODO your code goes here
return
date_sorter(time_s)