Step response of R L circuit

In [1]:

    

from lcapy import Circuit, s
cct = Circuit("""
V1 1 0 {u(t)}; down
R1 1 2 4; right=2
L1 2 3 0.5; down=2
W1 0 3; right
""")
cct.draw()


    

In [2]:

    

cct[2].V(s)


    

    
Out[2]:





$$\frac{1}{s + 8}$$

In [3]:

    

%matplotlib inline
ax = cct[2].v.plot()


    

In [4]:

    

ax = cct[2].v.plot()


    

In [5]:

    

ax = cct.R1.i.plot()


    

In [6]:

    

cct.s_model().draw()


    

In [7]:

    

cct[2].V(s).ZPK()


    

    
Out[7]:





$$\frac{1}{s + 8}$$

In [8]:

    

cct[2].V(s).poles()


    

    
Out[8]:





$$\left\{ -8 : 1\right\}$$

In [9]:

    

cct[2].V(s).zeros()


    

    
Out[9]:





$$\left\{ \right\}$$

In [10]:

    

ax = cct[2].V(s).plot()