If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.



In [1]:

    
from six.moves import range



In [2]:

    
sum(filter(lambda x: x%3==0 or x%5==0, range(1000)))









    Out[2]:





233168



In [3]:

    
sum(x for x in range(1000) if x%3==0 or x%5==0)









    Out[3]:





233168