In [1]:

    

class Account:
    def __init__(self, id):
        self.id = id
        id = 666 
 
acc = Account(123)
print(acc.id)


    

    




123

In [2]:

    

confusion = {}
confusion[1] = 1
confusion['1'] = 2
confusion[1.0] = 4
 
somme = 0
for k in confusion:
    somme += confusion[k]
 
print(somme)
print(confusion)


    

    




6
{'1': 2, 1: 4}

In [3]:

    

x = True
y = False
z = False
 
if x or y and z:
    print "yes"
else:
    print "no"


    

    




yes

In [4]:

    

inventaire = [("pommes", 22),("melons", 4),("poires", 18),("fraises", 76),("prunes", 51)]
#Classer cette liste selon la quantité de chaque fruit par ordre décroissant


    

In [5]:

    

inventaire_inverse = [(qtt, nom_fruit) for nom_fruit, qtt in inventaire]
inventaire_inverse.sort(reverse=True)
inventaire = [(nom_fruit, qtt) for qtt , nom_fruit in inventaire_inverse]
print(inventaire)


    

    




[('fraises', 76), ('prunes', 51), ('pommes', 22), ('poires', 18), ('melons', 4)]

In [6]:

    

import numpy as np
import numpy.random as nprnd
liste = nprnd.randint(1000, size=1000)
print type(list(liste))
print sum(list(liste))
%timeit sum(list(liste))


    

    




<type 'list'>
487128
10000 loops, best of 3: 67.9 µs per loop

In [7]:

    

print(reduce(lambda x,y: x+y, liste))
%timeit reduce(lambda x,y: x+y, liste)


    

    




487128
The slowest run took 5.09 times longer than the fastest. This could mean that an intermediate result is being cached.
10000 loops, best of 3: 117 µs per loop

In [8]:

    

print np.sum(liste)
%timeit np.sum(liste)


    

    




487128
The slowest run took 16.72 times longer than the fastest. This could mean that an intermediate result is being cached.
100000 loops, best of 3: 2.21 µs per loop

In [9]:

    

liste = [2,1,1,2,4,1,3]


    

In [10]:

    

sum([i for i in liste if i % 2 ==1])


    

    
Out[10]:





6

In [11]:

    

liste = [2,1,1,2,4,1,3]
list(set(liste))


    

    
Out[11]:





[1, 2, 3, 4]

In [12]:

    

%%writefile test.txt
Ceci est la ligne numéro 1
et la ligne numéro deux
d'un fichier texte qui au final contiendra
quatre lignes !


    

    




Overwriting test.txt

In [13]:

    

# 1) Comment ouvrir un fichier en lecture en traitant les exceptions possibles ?
my_file = 'test2.txt'
try:
    f = open(my_file)

    try:
        all = f.readlines()        
        print("FILE : {file} contains {numlines:06d} lines ".format(file=my_file,numlines=len(all)))
    except EXPECTED_EXCEPTION_TYPES as e:
        print("ERROR READING FILE : {file}".format(file=my_file))
        print(e)
    finally:
        f.close()

except (IOError, OSError) as e:
    print("ERROR OPENING FILE : {file}".format(file=my_file))
    print(e)
# https://pyformat.info/


    

    




ERROR OPENING FILE : test2.txt
[Errno 2] No such file or directory: 'test2.txt'

In [14]:

    

my_file = 'test.txt'
with open(my_file) as f:
    all = f.readlines()
    print all
    print("FILE : {file} contains {numlines:06d} lines ".format(file=my_file,numlines=len(all)))


    

    




['Ceci est la ligne num\xc3\xa9ro 1\n', 'et la ligne num\xc3\xa9ro deux\n', "d'un fichier texte qui au final contiendra\n", 'quatre lignes !']
FILE : test.txt contains 000004 lines 

In [ ]: