If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
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total=0 #initialize total to zero
for i in range(0, 1000): #for each number between 0 and 1000(non-inclusively)
if i % 3 == 0 or i % 5 == 0: #if i is divisible by 3 or 5
total += i #add i to the total
print(total) #The parantheses messed me up for so long! Little difference from python on codecademy, but a big problem!
In [ ]:
# This cell will be used for grading, leave it at the end of the notebook.