Square Root Function

Implement an integer and a float square root function

Integer Square Root Function



In [39]:

    
import math

def squareRoot_n(n, s, e):
    #print (n, s, e)
    if s == e:
        if s*s <= n:
            return s
        else:
            return s-1
    elif s > e:
        return e
    
    mid = int(s + (e-s) / 2)    
    sq = mid*mid
    
    if  sq == n:
        return mid
    elif sq > n:
        return squareRoot_n(n, s, mid-1)
    else:
        return squareRoot_n(n, mid+1, e) 


def squareRoot(n):
    return squareRoot_n(n, 0, n)



In [ ]:

    
for i in range(1000):  
    sq = squareRoot(i)
    expected = int(math.sqrt(i))
    assert sq == expected, "fail {} / true:{}".format(sq,expected)
print ("All tests PASS")

Float Square Root



In [ ]: