If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
In [31]:
def Euler_1(x):
total = 0
n = 0
while n < x:
if n % 3 == 0:
total = total + n
elif n % 5 == 0:
total = total + n
else:
total = total
n += 1
return total
print(Euler_1(1000))
In [23]:
# This cell will be used for grading, leave it at the end of the notebook.