If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
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n = list(range(1,1000))
def sum(x):
total = 0
for a in x:
if a % 3 == 0 or a % 5 == 0:
total += a
return total
print(sum(n))
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