In the previous lecture, we went over the basics of functions. Here, we'll expand a little bit on some of the finer points of function arguments that can both be useful but also be huge sources of confusion. By the end of the lecture, you should be able to:
In the previous lecture we learned about positional arguments. As the name implies, position is key:
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def pet_names(name1, name2):
print("Pet 1: ", name1)
print("Pet 2: ", name2)
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pet1 = "King"
pet2 = "Reginald"
pet_names(pet1, pet2) # pet1 variable, then pet2 variable
pet_names(pet2, pet1) # notice we've switched the order in which they're passed to the function
In this example, we switched the ordering of the arguments between the two function calls; consequently, the ordering of the arguments inside the function were also flipped. Hence, positional: position matters.
In contrast, Python also has keyword arguments, where order no longer matters as long as you specify the keyword. We can use the same pet_names function as before.
Only this time, we'll use the names of the arguments themselves (aka, keywords):
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pet1 = "Rocco"
pet2 = "Lucy"
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pet_names(name1 = pet1, name2 = pet2)
pet_names(name2 = pet2, name1 = pet1)
As you can see, we used the names of the arguments from the function header itself (go back to the previous slide to see the definition of pet_names if you don't remember), setting them equal to the variable we wanted to use for that argument.
Consequently, order doesn't matter--Python can see that, in both function calls, we're setting name1 = pet1 and name2 = pet2.
Keyword arguments are extremely useful when it comes to default arguments.
Ordering of the keyword arguments doesn't matter; that's why we can specify some of the default parameters by keyword, leaving others at their defaults, and Python doesn't complain.
Here's an important distinction, though:
In essence, you can't mix-and-match the ordering of positional and default arguments using keywords.
Here's an example of this behavior in action:
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# Here's our function with a default argument.
# x comes first (required), y comes second (default)
def pos_def(x, y = 10):
return x + y
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# Here, we've specified both arguments, using the keyword format.
z = pos_def(x = 10, y = 20)
print(z)
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# We're still using the keyword format, which allows us to reverse their ordering.
z = pos_def(y = 20, x = 10)
print(z)
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# But *only* specifying the default argument is a no-no.
z = pos_def(y = 20)
print(z)
There are instances where you'll want to pass in an arbitrary number of arguments to a function, a number which isn't known until the function is called and could change from call to call!
On one hand, you could consider just passing in a single list, thereby obviating the need. That's more or less what actually happens here, but the syntax is a tiny bit different.
Here's an example: a function which lists out pizza toppings. Note the format of the input argument(s):
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def make_pizza(*toppings):
print("Making a pizza with the following toppings:")
for topping in toppings:
print(" - ", topping)
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make_pizza("pepperoni")
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make_pizza("pepperoni", "banana peppers", "green peppers", "mushrooms")
Inside the function, the arguments are basically treated as a list: in fact, it is a list.
So why not just make the input argument a single variable which is a list?
Convenience.
In some sense, it's more intuitive to the programmer calling the function to just list out a bunch of things, rather than putting them all in a list structure first. But that argument could go either way depending on the person and the circumstance, most likely.
With variable-length arguments, you may very well ask: this is cool, but it doesn't seem like I can make keyword arguments work in this setting? And to that I would say, absolutely correct!
So we have a slight variation to accommodate keyword arguments in the realm of including arbitrary numbers of arguments:
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def build_profile(**user_info):
profile = {}
for key, value in user_info.items(): # This is how you iterate through the key/value pairs of dictionaries.
profile[key] = value
return profile
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profile = build_profile(firstname = "Shannon", lastname = "Quinn", university = "UGA")
print(profile)
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profile = build_profile(name = "Shannon Quinn", department = "Computer Science")
print(profile)
Instead of one star (*) in the function header, there are two (**). And yes, instead of a list when we get to the inside of the function, now we basically have a dictionary!
Arbitrary arguments (either "lists" or "dictionaries") can be mixed with positional arguments, as well as with each other.
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def build_better_profile(firstname, lastname, *nicknames, **user_info):
profile = {'First Name': firstname, 'Last Name': lastname}
for key, value in user_info.items():
profile[key] = value
profile['Nicknames'] = nicknames
return profile
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profile = build_better_profile("Shannon", "Quinn", "Professor", "Doctor", "Master of Science",
department = "Computer Science", university = "UGA")
for key, value in profile.items():
print(key, ": ", value)
That last example had pretty much everything.
firstname and lastname*nicknames is an arbitrary list of arguments, so anything beyond the positional / keyword (or default!) arguments will be considered part of this aggregate**user_info is comprised of any key-value pairs that are not among the default arguments; in this case, those are department and university(Don't worry--we won't use these mechanisms too often in this class. They're also not used too often in practice, but it's still good to know how to read them when they do show up)
This is arguably one of the trickiest parts of programming, so please ask questions if you're having trouble.
Let's start with an example to illustrate what's this is. Take the following code:
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def magic_function(x):
x = 20
print("Inside function: ", x)
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x = 10
print("Before function: ", x)
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magic_function(x)
If we wrote another print statement, what would print out? 10? 20? Something else?
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print("After function: ", x)
It prints 10. Before explaining, let's take another example.
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def magic_function2(x):
x[0] = 20
print("Inside function: {}".format(x))
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x = [10, 10]
print("Before function: {}".format(x))
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magic_function2(x)
What would a print statement now print out? [10, 10]? [20, 10]? Something else?
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print("After function: ", x)
It prints [20, 10].
To recap, what we've seen is that
Explaining these seemingly-divergent behaviors is the tricky part, but to give you the punchline:
StackOverflow has a great gif to represent this process in pictures.
So what are these mysterious references?
Imagine you're throwing a party for some friends who have never visited your house before. They ask you for directions (or, given we live in the age of Google Maps, they ask for your home address).
Rather than try to hand them your entire house, or put your physical house on Google Maps (I mean this quite literally), what do you do? You write down your home address on a piece of paper (or, realistically, send a text message).
This is not your house, but it is a reference to your house. It's small, compact, and easy to give out--as opposed to your physical, literal home--while intrinsically providing a path to the real thing.
So it is with references. They hearken back to ye olde computre ayge when fast memory was a precious commodity measured in kilobytes, which is not enough memory to store even the Facebook home page.
It was, however, enough to store the address. These addresses, or references, would point to specific locations in the larger, much slower main memory hard disks where all the larger data objects would be saved.
Scanning through larger, extremely slow hard disks looking for the object itself would be akin to driving through every neighborhood in the city of Atlanta looking for a specific house. Possible, sure, but not very efficient. Much faster to have the address in-hand and drive directly there whenever you need to.
Very astute. This has to do with a subtle but important difference in how Python passes variables of different types to functions.
Think of references as "arrows"--they refer to your actual objects, like lists or NumPy arrays. The name with which you refer to your object is the reference.
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some_list = [1, 2, 3]
# some_list -> reference to my list
# [1, 2, 3] -> the actual, physical list
Whenever you operate on some_list, you have to traverse the "arrow" to the object itself, which is separate. Again, think of the house analogy: whenever you want to clean your house, you have to follow your reference to it first.
This YouTube video isn't exactly the same thing, since C++ handles this much more explicitly than Python does. But if you substitute "references" for "pointers", and ignore the little code snippets, it's more or less describing precisely this concept.
There's a slight wrinkle in this pass-by-value, pass-by-reference story... Using what you've learned so far, what do you think the output of this function will be?
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def set_to_none(some_list):
some_list = None # sets the reference "some_list" to point at nothing
print("In function: ", some_list)
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a_list = [1, 2, 3]
print("Before function: {}".format(a_list))
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set_to_none(a_list)
Now the function has finished; if we print out the list, what will we get?
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print(a_list)
"But," you begin, "you said objects like lists are pass-by-reference, and therefore any changes made in functions are permanent!"
And you'd be... mostly right. Because references are tricky little buggers.
Here's the thing: everything in Python is pass-by-value. But references to non-"primitive" objects, like lists, still exist and have specific effects.
Let's parse this out.
We already know any "basic" data type in Python is passed by value, or copied. So any modifications we make inside a function go away outside the function (unless we return it, of course). This has not changed.
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def modify_int(x):
x = 9238493 # Works as long as we're in this function...once we leave, it goes away.
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x = 10
modify_int(x)
print(x) # Even though we set x to some other value in the function, that was only a copy
When it comes to more "complicated" data types--strings, lists, dictionaries, sets, tuples, generators--we have to deal with two parts: the reference, and the object itself.
When we pass one of the objects into a function, the reference is passed-by-value...meaning the reference is copied!
But since it points to the same original object as the original reference, any modifications made to the object persist, even though the copied reference goes away after the function ends.
It's like I sent out two text messages with my home address. I've copied the reference, though I clearly have not copied my house. And if a recipient deletes that text message, well--they only deleted the reference, not my house.
Upshot being: to persist modifications made inside a function to an object, you have to modify the object itself, not the reference. Setting the reference to None is a modification of the reference, not the object.
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def modify_list(x):
x[0] = 9238493 # Here, we're modifying a specific part of the object, so this will persist!
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a_list = [1, 2, 3]
print(a_list) # Before
modify_list(a_list)
print(a_list) # After
Think of it this way:
x[0] modifies the list itself, of which there is only 1.x = None is modifying the reference to the list, of which we have only a COPY of in the function. This copy then goes away when the function ends, and we're left with the original reference, which still points to the original list!Clear as mud? Excellent!
Here is one more example, which illustrates why it's better to think of Python variables as two parts: one part bucket of data (the actual object), and one part pointer to a bucket (the name).
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x = [1, 2, 3] # Create a list, assign it to x.
y = x # Assign a new variable y to x.
x.append(4) # Append an element to the list x.
print(y) # Print ** y **
Notice how we called append on the variable x, and yet when we print y, we see the 4 there as well!
This is because x and y are both references that point to the same object. As such, if we reassign x to point to something else, y will still point to the first list.
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x = 5 # reassign x
print(x)
print(y) # same as before!
1: Give some examples for when we'd want to use keyword arguments, arbitrary numbers of arguments, and key-value arguments.
2: Let's say I wanted to write a function to store travel information on a per-person basis: this function would let people specify an unbounded number of cities they'd visited, as well as their name, to tie the locations to them. Would this be a legal way of defining the function? Why or why not? def places_visited(*cities, name_of_traveler):
3: Let's say I wanted to write a function, add1(), which takes an integer as input and adds 1 to it. We know that integers are passed by value, so therefore any changes made to the argument inside the function are discarded when the function finishes. Are there any additional changes I could make so that this function will indeed give me a value that is 1 + the input argument?
4: Write a function swap(x, y) that swaps the values of the arguments x and y, without using a return statement. Can you do this with integer data types, or do you need to "augment" their type?
5: Describe what's happening in the code below. What will the value of x be at the two print statements? Why?
x = [1, 2, 3]
def func(x = 10):
x = 20
func()
print(x)
func(x)
print(x)