by Alejandro Correa Bahnsen & Iván Torroledo
version 1.2, Feb 2018
This notebook is licensed under a Creative Commons Attribution-ShareAlike 3.0 Unported License. Special thanks goes to Kevin Markham
In [1]:
import pandas as pd
import zipfile
with zipfile.ZipFile('../datasets/titanic.csv.zip', 'r') as z:
f = z.open('titanic.csv')
titanic = pd.read_csv(f, sep=',', index_col=0)
titanic.head()
Out[1]:
In [2]:
# check for missing values
titanic.isnull().sum()
Out[2]:
One possible strategy is to drop missing values:
In [3]:
# drop rows with any missing values
titanic.dropna().shape
Out[3]:
In [4]:
# drop rows where Age is missing
titanic[titanic.Age.notnull()].shape
Out[4]:
Sometimes a better strategy is to impute missing values:
In [5]:
# mean Age
titanic.Age.mean()
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In [6]:
# median Age
titanic.Age.median()
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In [7]:
# most frequent Age
titanic.Age.mode()
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In [8]:
# fill missing values for Age with the median age
titanic.Age.fillna(titanic.Age.median(), inplace=True)
Another strategy would be to build a KNN model just to impute missing values. How would we do that?
If values are missing from a categorical feature, we could treat the missing values as another category. Why might that make sense?
How do we choose between all of these strategies?
In [9]:
titanic.head(10)
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In [10]:
# encode Sex_Female feature
titanic['Sex_Female'] = titanic.Sex.map({'male':0, 'female':1})
In [11]:
# create a DataFrame of dummy variables for Embarked
embarked_dummies = pd.get_dummies(titanic.Embarked, prefix='Embarked')
embarked_dummies.drop(embarked_dummies.columns[0], axis=1, inplace=True)
# concatenate the original DataFrame and the dummy DataFrame
titanic = pd.concat([titanic, embarked_dummies], axis=1)
In [12]:
titanic.head(1)
Out[12]:
In [13]:
# define X and y
feature_cols = ['Pclass', 'Parch', 'Age', 'Sex_Female', 'Embarked_Q', 'Embarked_S']
X = titanic[feature_cols]
y = titanic.Survived
# train/test split
from sklearn.model_selection import train_test_split
X_train, X_test, y_train, y_test = train_test_split(X, y, random_state=1)
# train a logistic regression model
from sklearn.linear_model import LogisticRegression
logreg = LogisticRegression(C=1e9)
logreg.fit(X_train, y_train)
# make predictions for testing set
y_pred_class = logreg.predict(X_test)
# calculate testing accuracy
from sklearn import metrics
print(metrics.accuracy_score(y_test, y_pred_class))
In [14]:
# predict probability of survival
y_pred_prob = logreg.predict_proba(X_test)[:, 1]
In [15]:
%matplotlib inline
import matplotlib.pyplot as plt
plt.rcParams['figure.figsize'] = (8, 6)
plt.rcParams['font.size'] = 14
In [16]:
# plot ROC curve
fpr, tpr, thresholds = metrics.roc_curve(y_test, y_pred_prob)
plt.plot(fpr, tpr)
plt.xlim([0.0, 1.0])
plt.ylim([0.0, 1.0])
plt.xlabel('False Positive Rate (1 - Specificity)')
plt.ylabel('True Positive Rate (Sensitivity)')
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In [17]:
# calculate AUC
print(metrics.roc_auc_score(y_test, y_pred_prob))
Besides allowing you to calculate AUC, seeing the ROC curve can help you to choose a threshold that balances sensitivity and specificity in a way that makes sense for the particular context.
In [18]:
# histogram of predicted probabilities grouped by actual response value
df = pd.DataFrame({'probability':y_pred_prob, 'actual':y_test})
df.hist(column='probability', by='actual', sharex=True, sharey=True)
Out[18]:
In [19]:
# ROC curve using y_pred_class - WRONG!
fpr, tpr, thresholds = metrics.roc_curve(y_test, y_pred_class)
plt.plot(fpr, tpr)
Out[19]:
In [20]:
# AUC using y_pred_class - WRONG!
print(metrics.roc_auc_score(y_test, y_pred_class))
If you use y_pred_class, it will interpret the zeros and ones as predicted probabilities of 0% and 100%.
Motivation: Need a way to choose between machine learning models
Initial idea: Train and test on the same data
Alternative idea: Train/test split
In [21]:
from sklearn.linear_model import LogisticRegression
from sklearn.model_selection import train_test_split
from sklearn import metrics
# define X and y
feature_cols = ['Pclass', 'Parch', 'Age', 'Sex_Female', 'Embarked_Q', 'Embarked_S']
X = titanic[feature_cols]
y = titanic.Survived
In [22]:
# train/test split
X_train, X_test, y_train, y_test = train_test_split(X, y, random_state=1)
# train a logistic regression model
logreg = LogisticRegression(C=1e9)
logreg.fit(X_train, y_train)
# make predictions for testing set
y_pred_class = logreg.predict(X_test)
# calculate testing accuracy
print(metrics.accuracy_score(y_test, y_pred_class))
In [23]:
# train/test split
X_train, X_test, y_train, y_test = train_test_split(X, y, random_state=2)
# train a logistic regression model
logreg = LogisticRegression(C=1e9)
logreg.fit(X_train, y_train)
# make predictions for testing set
y_pred_class = logreg.predict(X_test)
# calculate testing accuracy
print(metrics.accuracy_score(y_test, y_pred_class))
In [24]:
# train/test split
X_train, X_test, y_train, y_test = train_test_split(X, y, random_state=3)
# train a logistic regression model
logreg = LogisticRegression(C=1e9)
logreg.fit(X_train, y_train)
# make predictions for testing set
y_pred_class = logreg.predict(X_test)
# calculate testing accuracy
print(metrics.accuracy_score(y_test, y_pred_class))
train test spliting create bias due to the intrinsic randomness in the sets selection
Diagram of 5-fold cross-validation:
In [27]:
# simulate splitting a dataset of 25 observations into 5 folds
from sklearn.cross_validation import KFold
kf = KFold(25, n_folds=5, shuffle=False)
# print the contents of each training and testing set
print('{} {:^61} {}'.format('Iteration', 'Training set observations', 'Testing set observations'))
for iteration, data in enumerate(kf, start=1):
print('{:^9} {} {:^25}'.format(str(iteration), str(data[0]), str(data[1])))
In [28]:
# Create k-folds
kf = KFold(X.shape[0], n_folds=10, random_state=0)
results = []
for train_index, test_index in kf:
X_train, X_test = X.iloc[train_index], X.iloc[test_index]
y_train, y_test = y.iloc[train_index], y.iloc[test_index]
# train a logistic regression model
logreg = LogisticRegression(C=1e9)
logreg.fit(X_train, y_train)
# make predictions for testing set
y_pred_class = logreg.predict(X_test)
# calculate testing accuracy
results.append(metrics.accuracy_score(y_test, y_pred_class))
In [29]:
pd.Series(results).describe()
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In [30]:
from sklearn.cross_validation import cross_val_score
logreg = LogisticRegression(C=1e9)
results = cross_val_score(logreg, X, y, cv=10, scoring='accuracy')
In [31]:
pd.Series(results).describe()
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Advantages of cross-validation:
Advantages of train/test split:
cross_val_score function does this by defaultRepeated cross-validation
Creating a hold-out set
Feature engineering and selection within cross-validation iterations
Now that we've gone over the basics of validation, and cross-validation, it's time to go into even more depth regarding model selection.
The issues associated with validation and cross-validation are some of the most important aspects of the practice of machine learning. Selecting the optimal model for your data is vital, and is a piece of the problem that is not often appreciated by machine learning practitioners.
Of core importance is the following question:
If our estimator is underperforming, how should we move forward?
The answer is often counter-intuitive. In particular, Sometimes using a more complicated model will give worse results. Also, Sometimes adding training data will not improve your results. The ability to determine what steps will improve your model is what separates the successful machine learning practitioners from the unsuccessful.
For this section, we'll work with a simple 1D regression problem. This will help us to
easily visualize the data and the model, and the results generalize easily to higher-dimensional
datasets. We'll explore a simple linear regression problem.
This can be accomplished within scikit-learn with the sklearn.linear_model module.
We'll create a simple nonlinear function that we'd like to fit
In [32]:
%matplotlib inline
import numpy as np
import matplotlib.pyplot as plt
def test_func(x, err=0.5):
y = 10 - 1. / (x + 0.1)
if err > 0:
y = np.random.normal(y, err)
return y
Now let's create a realization of this dataset:
In [33]:
def make_data(N=40, error=1.0, random_seed=1):
# randomly sample the data
np.random.seed(1)
X = np.random.random(N)[:, np.newaxis]
y = test_func(X.ravel(), error)
return X, y
In [34]:
X, y = make_data(40, error=1)
plt.scatter(X.ravel(), y);
Now say we want to perform a regression on this data. Let's use the built-in linear regression function to compute a fit:
In [35]:
X_test = np.linspace(-0.1, 1.1, 500)[:, None]
from sklearn.linear_model import LinearRegression
from sklearn.metrics import mean_squared_error
model = LinearRegression()
model.fit(X, y)
y_test = model.predict(X_test)
plt.scatter(X.ravel(), y)
plt.plot(X_test.ravel(), y_test,c='r')
plt.title("mean squared error: {0:.3g}".format(mean_squared_error(model.predict(X), y)));
We have fit a straight line to the data, but clearly this model is not a good choice. We say that this model is biased, or that it under-fits the data.
Let's try to improve this by creating a more complicated model. We can do this by adding degrees of freedom, and computing a polynomial regression over the inputs. Scikit-learn makes this easy with the PolynomialFeatures preprocessor, which can be pipelined with a linear regression.
Let's make a convenience routine to do this:
In [36]:
from sklearn.preprocessing import PolynomialFeatures
from sklearn.linear_model import LinearRegression
Now we'll use this to fit a quadratic curve to the data.
In [37]:
X_poly = PolynomialFeatures(degree=2).fit_transform(X)
X_test_poly = PolynomialFeatures(degree=2).fit_transform(X_test)
In [38]:
model = LinearRegression()
model.fit(X_poly, y)
y_test = model.predict(X_test_poly)
plt.scatter(X.ravel(), y)
plt.plot(X_test.ravel(), y_test,c='r')
plt.title("mean squared error: {0:.3g}".format(mean_squared_error(model.predict(X_poly), y)));
This reduces the mean squared error, and makes a much better fit. What happens if we use an even higher-degree polynomial?
In [39]:
X_poly = PolynomialFeatures(degree=30).fit_transform(X)
X_test_poly = PolynomialFeatures(degree=30).fit_transform(X_test)
model = LinearRegression()
model.fit(X_poly, y)
y_test = model.predict(X_test_poly)
plt.scatter(X.ravel(), y)
plt.plot(X_test.ravel(), y_test,c='r')
plt.title("mean squared error: {0:.3g}".format(mean_squared_error(model.predict(X_poly), y)))
plt.ylim(-4, 14);
When we increase the degree to this extent, it's clear that the resulting fit is no longer reflecting the true underlying distribution, but is more sensitive to the noise in the training data. For this reason, we call it a high-variance model, and we say that it over-fits the data.
Just for fun, let's use IPython's interact capability (only in IPython 2.0+) to explore this interactively:
In [40]:
from ipywidgets import interact
def plot_fit(degree=1, Npts=50):
X, y = make_data(Npts, error=1)
X_test = np.linspace(-0.1, 1.1, 500)[:, None]
X_poly = PolynomialFeatures(degree=degree).fit_transform(X)
X_test_poly = PolynomialFeatures(degree=degree).fit_transform(X_test)
model = LinearRegression()
model.fit(X_poly, y)
y_test = model.predict(X_test_poly)
plt.scatter(X.ravel(), y)
plt.plot(X_test.ravel(), y_test)
plt.title("mean squared error: {0:.3g}".format(mean_squared_error(model.predict(X_poly), y)))
plt.ylim(-4, 14)
interact(plot_fit, degree=[1, 40], Npts=[2, 100]);
Clearly, computing the error on the training data is not enough (we saw this previously). As above, we can use cross-validation to get a better handle on how the model fit is working.
Let's do this here, again using the validation_curve utility. To make things more clear, we'll use a slightly larger dataset:
In [41]:
X, y = make_data(120, error=1.0)
plt.scatter(X, y);
In [42]:
from sklearn.model_selection import validation_curve
In [43]:
def rms_error(model, X, y):
y_pred = model.predict(X)
return np.sqrt(np.mean((y - y_pred) ** 2))
In [44]:
from sklearn.pipeline import make_pipeline
def PolynomialRegression(degree=2, **kwargs):
return make_pipeline(PolynomialFeatures(degree),
LinearRegression(**kwargs))
In [45]:
degree = np.arange(0, 18)
val_train, val_test = validation_curve(PolynomialRegression(), X, y,
'polynomialfeatures__degree', degree, cv=7,
scoring=rms_error)
Now let's plot the validation curves:
In [46]:
def plot_with_err(x, data, **kwargs):
mu, std = data.mean(1), data.std(1)
lines = plt.plot(x, mu, '-', **kwargs)
plt.fill_between(x, mu - std, mu + std, edgecolor='none',
facecolor=lines[0].get_color(), alpha=0.2)
plot_with_err(degree, val_train, label='training scores')
plot_with_err(degree, val_test, label='validation scores')
plt.xlabel('degree'); plt.ylabel('rms error')
plt.legend();
Notice the trend here, which is common for this type of plot.
For a small model complexity, the training error and validation error are very similar. This indicates that the model is under-fitting the data: it doesn't have enough complexity to represent the data. Another way of putting it is that this is a high-bias model.
As the model complexity grows, the training and validation scores diverge. This indicates that the model is over-fitting the data: it has so much flexibility, that it fits the noise rather than the underlying trend. Another way of putting it is that this is a high-variance model.
Note that the training score (nearly) always improves with model complexity. This is because a more complicated model can fit the noise better, so the model improves. The validation data generally has a sweet spot, which here is around 5 terms.
Here's our best-fit model according to the cross-validation:
In [47]:
model = PolynomialRegression(4).fit(X, y)
plt.scatter(X, y)
plt.plot(X_test, model.predict(X_test),c='r');
As you might guess, the exact turning-point of the tradeoff between bias and variance is highly dependent on the number of training points used. Here we'll illustrate the use of learning curves, which display this property.
The idea is to plot the mean-squared-error for the training and test set as a function of Number of Training Points
In [51]:
from sklearn.learning_curve import learning_curve
def plot_learning_curve(degree=3):
train_sizes = np.linspace(0.05, 1, 20)
N_train, val_train, val_test = learning_curve(PolynomialRegression(degree),
X, y, train_sizes, cv=5,
scoring=rms_error)
plot_with_err(N_train, val_train, label='training scores')
plot_with_err(N_train, val_test, label='validation scores')
plt.xlabel('Training Set Size'); plt.ylabel('rms error')
plt.ylim(0, 3)
plt.xlim(5, 80)
plt.legend()
Let's see what the learning curves look like for a linear model:
In [52]:
plot_learning_curve(1)
This shows a typical learning curve: for very few training points, there is a large separation between the training and test error, which indicates over-fitting. Given the same model, for a large number of training points, the training and testing errors converge, which indicates potential under-fitting.
As you add more data points, the training error will never increase, and the testing error will never decrease (why do you think this is?)
It is easy to see that, in this plot, if you'd like to reduce the MSE down to the nominal value of 1.0 (which is the magnitude of the scatter we put in when constructing the data), then adding more samples will never get you there. For $d=1$, the two curves have converged and cannot move lower. What about for a larger value of $d$?
In [53]:
plot_learning_curve(3)
Here we see that by adding more model complexity, we've managed to lower the level of convergence to an rms error of 1.0!
What if we get even more complex?
In [54]:
plot_learning_curve(10)
For an even more complex model, we still converge, but the convergence only happens for large amounts of training data.
So we see the following:
Thus these curves can give you hints about how you might improve a sub-optimal model. If the curves are already close together, you need more model complexity. If the curves are far apart, you might also improve the model by adding more data.
To make this more concrete, imagine some telescope data in which the results are not robust enough. You must think about whether to spend your valuable telescope time observing more objects to get a larger training set, or more attributes of each object in order to improve the model. The answer to this question has real consequences, and can be addressed using these metrics.
Intuitively, precision is the ability of the classifier not to label as positive a sample that is negative, and recall is the ability of the classifier to find all the positive samples.
The F-measure ($F_\beta$ and $F_1$ measures) can be interpreted as a weighted harmonic mean of the precision and recall. A $F_\beta$ measure reaches its best value at 1 and its worst score at 0. With $\beta = 1$, $F_\beta$ and $F_1$ are equivalent, and the recall and the precision are equally important.
In [55]:
import pandas as pd
import zipfile
with zipfile.ZipFile('../datasets/titanic.csv.zip', 'r') as z:
f = z.open('titanic.csv')
titanic = pd.read_csv(f, sep=',', index_col=0)
titanic.head()
# fill missing values for Age with the median age
titanic.Age.fillna(titanic.Age.median(), inplace=True)
# define X and y
feature_cols = ['Pclass', 'Parch', 'Age']
X = titanic[feature_cols]
y = titanic.Survived
# train/test split
from sklearn.cross_validation import train_test_split
X_train, X_test, y_train, y_test = train_test_split(X, y, random_state=1)
# train a logistic regression model
from sklearn.linear_model import LogisticRegression
logreg = LogisticRegression(C=1e9)
logreg.fit(X_train, y_train)
# make predictions for testing set
y_pred_class = logreg.predict(X_test)
In [56]:
from sklearn.metrics import confusion_matrix
confusion_matrix(y_test, y_pred_class)
Out[56]:
In [57]:
from sklearn.metrics import precision_score, recall_score, f1_score
print('precision_score ', precision_score(y_test, y_pred_class))
print('recall_score ', recall_score(y_test, y_pred_class))
In [58]:
print('f1_score ', f1_score(y_test, y_pred_class))
We've gone over several useful tools for model validation
These tools are powerful means of evaluating your model on your data.