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%matplotlib inline
from matplotlib import pyplot as plt
import numpy as np
Write a function tokenize that takes a string of English text returns a list of words. It should also remove stop words, which are common short words that are often removed before natural language processing. Your function should have the following logic:
splitlines.filter function to remove all punctuation.stop_words is a list, remove all occurences of the words in the list.stop_words is a space delimeted string of words, split them and remove them.
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def tokenize(s, stop_words=None, punctuation='`~!@#$%^&*()_-+={[}]|\:;"<,>.?/}\t'):
"""Split a string into a list of words, removing punctuation and stop words."""
w = []
for line in s.splitlines(): #uses the splitlines function to split each of the lines in the input
w.extend(line.split(' '))
w = [''.join(filter(lambda c: c not in punctuation, word)) for word in w] # filters out the punctuation
if isinstance(stop_words, str):
stop_words = stop_words.split(' ')
if stop_words is not None: #calls the if statment to pull out the words if they are not nothing
w = [word for word in w if word not in stop_words]
w = [word.lower() for word in w if word]
return w #ends the function
tokenize(s='no @ the range, randy .. is !a',stop_words='the', punctuation='`~!@#$%^&*()_-+={[}]|\:;"<,>.?/}\t') #my check to see if it was working
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assert tokenize("This, is the way; that things will end", stop_words=['the', 'is']) == \
['this', 'way', 'that', 'things', 'will', 'end']
wasteland = """
APRIL is the cruellest month, breeding
Lilacs out of the dead land, mixing
Memory and desire, stirring
Dull roots with spring rain.
"""
assert tokenize(wasteland, stop_words='is the of and') == \
['april','cruellest','month','breeding','lilacs','out','dead','land',
'mixing','memory','desire','stirring','dull','roots','with','spring',
'rain']
Write a function count_words that takes a list of words and returns a dictionary where the keys in the dictionary are the unique words in the list and the values are the word counts.
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def count_words(data):
wc = {}
for word in data:
if word in wc:
wc[word] += 1
else:
wc[word] = 1
return wc
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assert count_words(tokenize('this and the this from and a a a')) == \
{'a': 3, 'and': 2, 'from': 1, 'the': 1, 'this': 2}
Write a function sort_word_counts that return a list of sorted word counts:
(word, count) tuple.sorted function with a custom key and reverse
argument.
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def sort_word_counts(wc):
"""Return a list of 2-tuples of (word, count), sorted by count descending."""
return list(sorted(wc.items(),key=lambda x:x[1],reverse=True))
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assert sort_word_counts(count_words(tokenize('this and a the this this and a a a'))) == \
[('a', 4), ('this', 3), ('and', 2), ('the', 1)]
Perform a word count analysis on Chapter 1 of Moby Dick, whose text can be found in the file mobydick_chapter1.txt:
'the of and a to in is it that as'.swc.
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with open('mobydick_chapter1.txt') as ishmael:
raw=ishmael.read()
l=tokenize(raw,stop_words='the of and a to in is it that as')
c=count_words(l)
swc=sort_word_counts(c)
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assert swc[0]==('i',43)
assert len(swc)==848
Create a "Cleveland Style" dotplot of the counts of the top 50 words using Matplotlib. If you don't know what a dotplot is, you will have to do some research...
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# YOUR CODE HERE
raise NotImplementedError()
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assert True # use this for grading the dotplot