If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
In [4]:
s=1000
a=list(range(s))
def asd(x):
result=0
for b in x:
if b % 3 ==0:
result +=b
elif b%5==0:
result +=b
return result
print(asd(a))
In [ ]:
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