In [41]:
import numpy as np
import matplotlib.pyplot as plt
from scipy.special import exp1 as W
from numpy.random import randn
import matplotlib as mpl
font = {'family' : 'DeJaVu sans',
'weight' : 'normal',
'size' : 16}
mpl.rc('font', **font)
def newfig(title='?', xlabel='?', ylabel='?', xscale='linear', yscale='linear', xlim=None, ylim=None, size_inches=(14, 7)):
fig, ax = plt.subplots()
fig.set_size_inches(size_inches)
if isinstance(title, tuple):
ax.set_title(title[0], {'fontsize' : title[1]})
else:
ax.set_title(title)
if isinstance(xlabel, tuple):
ax.set_xlabel(xlabel[0], {'size' :xlabel[1]})
else:
ax.set_xlabel(xlabel)
if isinstance(ylabel, tuple):
ax.set_ylabel(ylabel[0], {'size' : ylabel[1]})
else:
ax.set_ylabel(ylabel)
if xlim is not None: ax.set_xlim(xlim)
if ylim is not None: ax.set_ylim(ylim)
ax.set_xscale(xscale); ax.set_yscale(yscale)
ax.grid()
return ax
The change of head in a strip of land with width $L$ [m] between two ditches caused by a sudden change of water level equal to $A$ [m] at the left ditch and $B$ [m] at the right ditch, can be computed using the formula that is valid for an infinite aquifer (x>0) bounded by surface water at (x=0), if we apply superposition. The formula for the infinite aquifer is $$s(x, t) = A\, \mbox{erfc}\left(x \sqrt{\frac{S}{4 kD t}}\right)$$
In preparation of the superposition, a superposition scheme is drawn (see figure), showing the strip of land in dark yellow and the first few of the infinite series of mirror ditches. Error show the direction and size of the change of head at all ditches at $t=0$. Is this scheme correct? Explain why or why not that is the case.
The first term of formula for drainage of a strip of land in which the head is at $t=0$ is uniform and equal to A [m] above the ditches on either side is given by
$$s(x,t) \approx A \frac 4 \pi \cos \left(\frac \pi 2 \frac {x}{b}\right)\exp\left(-\left(\frac \pi {2}\right)^2\frac t T \right),\,\,\,\,\,T=\frac {b^2 S}{kD t}$$The simplified Theis solution for the drawdown due to a pumping well in a (un)confined aquifer reads
$$ s(r,t) = \frac{2.3 Q}{4 \pi kD} \log \left(\sqrt{\frac{2.25 kD t}{r^2 S}} \right)$$A pumping test was held, with an extraction of $Q = 2400 m^3/d$. The drawdown was measured in 3 observation wells.
The figure shows the measured drawdown in a number of observation wells as a function of $t/r^2$ versus time on logarithmic scale.
Answer the following questions
In [42]:
Q = 2400 # m3/d
kD = 775 # m2/d
S = 0.22 # [-]
sigma = 0.01
# Observation wells are at
r = [10, 25, 50] # m
m = ['x', '+', '*']
tmin = np.array([1, 2, 3, 5, 7, 10, 12, 15, 20, 25, 30, 40, 50, 60, 75, 90, 105, 120] +
[k for k in range(150, 901, 30)] + [k for k in range(1020, 5000, 120)], dtype=float)
td = tmin / (24 * 60)
ax = newfig(f'Pumping test, Q = {Q:.0f} m3/d', '$t/r^2 [d/m^2]$', 'Drawdown s [m]', xscale='log')
s = np.zeros((len(r), len(td)))
for ir, (ri, mi) in enumerate(zip(r, m)):
u = ri ** 2 * S / (4 * kD * td)
s[ir] = Q/ (4 * np.pi * kD) * W(u) + sigma * randn(len(td))
ax.plot(td/ri ** 2, s[ir], mi, label=f'piezometer at {ri:.0f} m')
ax.legend(fontsize=15)
Out[42]: