In [1]:

    

from cutiepy import *


    

In [2]:

    

x,y,z = xyz()
k = Ket('k', 10)
b = Bra('b', 10)
O = Operator('O', 10)
S = Superoperator('S', 10)
t = Scalar('t')


    

In [3]:

    

b*S*O*k


    

    
Out[3]:





$${{\langle {b}_{} |}{\mathcal{{S}_{}}}{\hat{O}_{}}{| {k}_{} \rangle}}$$

In [4]:

    

b*S*O*t**2*k


    

    
Out[4]:





$${{{\langle {b}_{} |}{\mathcal{{S}_{}}}{\hat{O}_{}}{| {k}_{} \rangle}}\tiny\times\normalsize{{ \left( {t} \right) }^{{2}}}}$$

In [5]:

    

b


    

    
Out[5]:





$$\text{Bra }{\langle {b}_{} |} \text{ on the space }\mathbb{C}^{10}\text{ without an attached numerical content.}$$

In [6]:

    

k1 = coherent(11, 1.5)
k1


    

    
Out[6]:





$$\text{Ket }{| {{\tiny\alpha\normalsize 1.50}}_{{\tiny N\normalsize 11}} \rangle} \text{ on the space }\mathbb{C}^{11}\text{ with numerical content: }$$
$$\begin{equation*}\left(\begin{array}{*{11}c}0.325\\0.487\\0.517\\0.447\\0.335\\\vdots\\0.138\\0.078\\0.041\\0.021\\0.010\\\end{array}\right)\end{equation*}$$

In [7]:

    

k2 = basis(5,3)
k2


    

    
Out[7]:





$$\text{Ket }{| {{3}}_{{\tiny N\normalsize 5}} \rangle} \text{ on the space }\mathbb{C}^{5}\text{ with numerical content: }$$
$$\begin{equation*}\left(\begin{array}{*{11}c}0.0\\0.0\\0.0\\1.0\\0.0\\\end{array}\right)\end{equation*}$$

In [8]:

    

evalf(k2*2)


    

    
Out[8]:





$$\text{Anonymous }\text{Ket }{| {\tiny\boxed{{K}_{c8371c8e...}}\normalsize}_{} \rangle} \text{ on the space }\mathbb{C}^{5}\text{ with numerical content: }$$
$$\begin{equation*}\left(\begin{array}{*{11}c}0.0\\0.0\\0.0\\2.0\\0.0\\\end{array}\right)\end{equation*}$$

In [9]:

    

expr = b*S*O*k
expr


    

    
Out[9]:





$${{\langle {b}_{} |}{\mathcal{{S}_{}}}{\hat{O}_{}}{| {k}_{} \rangle}}$$

In [10]:

    

bb = Bra(r'another\ one', 10)
subs(expr, b, bb)


    

    
Out[10]:





$${{\langle {another\ one}_{} |}{\mathcal{{S}_{}}}{\hat{O}_{}}{| {k}_{} \rangle}}$$