In [86]:

    

def total_number_of_rectangle(n):
    return_value = n
    
    for i in range(2, int(math.ceil(math.sqrt(n))) + 1):
        if pow(i,2) <= n:
            return_value += 1
            i2 = pow(i, 2)
            remaining = (n - i2) if (n - i2) > 0 else 0
        
            return_value += remaining/i
    
    print return_value


    

In [87]:

    

totalNumberOfRectanlge(10000)

totalNumberOfRectanlge(6)


    

    




46884
8

In [ ]: