In [1]:

    

l = list(range(100000))
print(l[:5])


    

    




[0, 1, 2, 3, 4]

In [2]:

    

print(l[-5:])


    

    




[99995, 99996, 99997, 99998, 99999]

In [3]:

    

print(len(l))


    

    




100000

In [4]:

    

%%timeit
all([i < 0 for i in l])


    

    




4.15 ms ± 117 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)

In [5]:

    

%%timeit
all(i < 0 for i in l)


    

    




469 ns ± 6.12 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

In [6]:

    

%%timeit
all([i >= 0 for i in l])


    

    




4.5 ms ± 57.3 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)

In [7]:

    

%%timeit
all(i >= 0 for i in l)


    

    




5.49 ms ± 255 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)

In [8]:

    

%%timeit
all(i < 50000 for i in l)


    

    




2.73 ms ± 37.4 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)

In [9]:

    

%%timeit
any([i >= 0 for i in l])


    

    




4.2 ms ± 183 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)

In [10]:

    

%%timeit
any(i >= 0 for i in l)


    

    




468 ns ± 4.8 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

In [11]:

    

%%timeit
any([i < 0 for i in l])


    

    




4.56 ms ± 180 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)

In [12]:

    

%%timeit
any(i < 0 for i in l)


    

    




5.33 ms ± 45.5 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)

In [13]:

    

%%timeit
any(i > 50000 for i in l)


    

    




2.78 ms ± 120 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)