Machine Learning Engineer Nanodegree

Unsupervised Learning

Project: Creating Customer Segments

Welcome to the third project of the Machine Learning Engineer Nanodegree! In this notebook, some template code has already been provided for you, and it will be your job to implement the additional functionality necessary to successfully complete this project. Sections that begin with 'Implementation' in the header indicate that the following block of code will require additional functionality which you must provide. Instructions will be provided for each section and the specifics of the implementation are marked in the code block with a 'TODO' statement. Please be sure to read the instructions carefully!

In addition to implementing code, there will be questions that you must answer which relate to the project and your implementation. Each section where you will answer a question is preceded by a 'Question X' header. Carefully read each question and provide thorough answers in the following text boxes that begin with 'Answer:'. Your project submission will be evaluated based on your answers to each of the questions and the implementation you provide.

Note: Code and Markdown cells can be executed using the Shift + Enter keyboard shortcut. In addition, Markdown cells can be edited by typically double-clicking the cell to enter edit mode.

Getting Started

In this project, you will analyze a dataset containing data on various customers' annual spending amounts (reported in monetary units) of diverse product categories for internal structure. One goal of this project is to best describe the variation in the different types of customers that a wholesale distributor interacts with. Doing so would equip the distributor with insight into how to best structure their delivery service to meet the needs of each customer.

The dataset for this project can be found on the UCI Machine Learning Repository. For the purposes of this project, the features 'Channel' and 'Region' will be excluded in the analysis — with focus instead on the six product categories recorded for customers.

Run the code block below to load the wholesale customers dataset, along with a few of the necessary Python libraries required for this project. You will know the dataset loaded successfully if the size of the dataset is reported.


In [1]:
# Import libraries necessary for this project
import numpy as np
import pandas as pd
from IPython.display import display # Allows the use of display() for DataFrames

# Import supplementary visualizations code visuals.py
import visuals as vs

# Pretty display for notebooks
%matplotlib inline

# Load the wholesale customers dataset
try:
    data = pd.read_csv("customers.csv")
    data.drop(['Region', 'Channel'], axis = 1, inplace = True)
    print "Wholesale customers dataset has {} samples with {} features each.".format(*data.shape)
except:
    print "Dataset could not be loaded. Is the dataset missing?"


Wholesale customers dataset has 440 samples with 6 features each.

Data Exploration

In this section, you will begin exploring the data through visualizations and code to understand how each feature is related to the others. You will observe a statistical description of the dataset, consider the relevance of each feature, and select a few sample data points from the dataset which you will track through the course of this project.

Run the code block below to observe a statistical description of the dataset. Note that the dataset is composed of six important product categories: 'Fresh', 'Milk', 'Grocery', 'Frozen', 'Detergents_Paper', and 'Delicatessen'. Consider what each category represents in terms of products you could purchase.


In [2]:
# Display a description of the dataset
display(data.describe())


Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
count 440.000000 440.000000 440.000000 440.000000 440.000000 440.000000
mean 12000.297727 5796.265909 7951.277273 3071.931818 2881.493182 1524.870455
std 12647.328865 7380.377175 9503.162829 4854.673333 4767.854448 2820.105937
min 3.000000 55.000000 3.000000 25.000000 3.000000 3.000000
25% 3127.750000 1533.000000 2153.000000 742.250000 256.750000 408.250000
50% 8504.000000 3627.000000 4755.500000 1526.000000 816.500000 965.500000
75% 16933.750000 7190.250000 10655.750000 3554.250000 3922.000000 1820.250000
max 112151.000000 73498.000000 92780.000000 60869.000000 40827.000000 47943.000000

Implementation: Selecting Samples

To get a better understanding of the customers and how their data will transform through the analysis, it would be best to select a few sample data points and explore them in more detail. In the code block below, add three indices of your choice to the indices list which will represent the customers to track. It is suggested to try different sets of samples until you obtain customers that vary significantly from one another.


In [3]:
# TODO: Select three indices of your choice you wish to sample from the dataset
indices = [11, 100 ,200]

# Create a DataFrame of the chosen samples
samples = pd.DataFrame(data.loc[indices], columns = data.keys()).reset_index(drop = True)
print "Chosen samples of wholesale customers dataset:"
display(samples)


Chosen samples of wholesale customers dataset:
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
0 13146 1124 4523 1420 549 497
1 11594 7779 12144 3252 8035 3029
2 3067 13240 23127 3941 9959 731

Question 1

Consider the total purchase cost of each product category and the statistical description of the dataset above for your sample customers.
What kind of establishment (customer) could each of the three samples you've chosen represent?
Hint: Examples of establishments include places like markets, cafes, and retailers, among many others. Avoid using names for establishments, such as saying "McDonalds" when describing a sample customer as a restaurant.

Answer:

  • Index 11 - Restaurant. The purchase cost of fresh product is more than average while those of other product categories are below average. A restaurant uses fresh product to serve meal.
  • Index 100 - Market or supermarket (mid or large size). Except for the fresh product of which the purchase cost is close to the average, the purchase costs of all other categories are above the average especially the grocery, the detergents paper and delicatessen. A market usually sells all kinds of items.
  • Index 200 - Retailer. The purchase costs of milk, grocery, frozen and detergents paper are above the average while the costs of others are much less than the average. Usually people go to retailers like convenient stores for fast food, milk and daily supplies.

Implementation: Feature Relevance

One interesting thought to consider is if one (or more) of the six product categories is actually relevant for understanding customer purchasing. That is to say, is it possible to determine whether customers purchasing some amount of one category of products will necessarily purchase some proportional amount of another category of products? We can make this determination quite easily by training a supervised regression learner on a subset of the data with one feature removed, and then score how well that model can predict the removed feature.

In the code block below, you will need to implement the following:

  • Assign new_data a copy of the data by removing a feature of your choice using the DataFrame.drop function.
  • Use sklearn.cross_validation.train_test_split to split the dataset into training and testing sets.
    • Use the removed feature as your target label. Set a test_size of 0.25 and set a random_state.
  • Import a decision tree regressor, set a random_state, and fit the learner to the training data.
  • Report the prediction score of the testing set using the regressor's score function.

In [4]:
from sklearn.cross_validation import train_test_split
from sklearn.tree import DecisionTreeRegressor

def feature_relevance(selected_feature):
    # TODO: Make a copy of the DataFrame, using the 'drop' function to drop the given feature
    new_data = data.copy()
    new_data.drop([selected_feature], axis = 1, inplace = True)

    # TODO: Split the data into training and testing sets using the given feature as the target
    X_train, X_test, y_train, y_test = train_test_split(new_data, data[selected_feature], test_size=0.25, random_state=0)

    # TODO: Create a decision tree regressor and fit it to the training set
    regressor = DecisionTreeRegressor(random_state=0)
    regressor.fit(X_train, y_train)

    # TODO: Report the score of the prediction using the testing set
    score = regressor.score(X_test, y_test)
    return score

for feature in data.columns:
    score = feature_relevance(feature)
    print('The score for {} is {}.'.format(feature, score))


The score for Fresh is -0.252469807688.
The score for Milk is 0.365725292736.
The score for Grocery is 0.602801978878.
The score for Frozen is 0.253973446697.
The score for Detergents_Paper is 0.728655181254.
The score for Delicatessen is -11.6636871594.

Question 2

Which feature did you attempt to predict? What was the reported prediction score? Is this feature necessary for identifying customers' spending habits?
Hint: The coefficient of determination, R^2, is scored between 0 and 1, with 1 being a perfect fit. A negative R^2 implies the model fails to fit the data.

Answer:

I tried a few features.

  • Detergents_Paper. The score is 0.73. This feature can be predicted from other features so it isn't necessary for identifying customers' spending habits.
  • Delicatessen. The score is -11.66. This feature cannot be predicted from other features so it is necessary for identifying customers' spending habits.
  • Milk. The score is 0.36. This feature can barely be predicted from other features so it is necessary for identifying customers' spending habits.

Visualize Feature Distributions

To get a better understanding of the dataset, we can construct a scatter matrix of each of the six product features present in the data. If you found that the feature you attempted to predict above is relevant for identifying a specific customer, then the scatter matrix below may not show any correlation between that feature and the others. Conversely, if you believe that feature is not relevant for identifying a specific customer, the scatter matrix might show a correlation between that feature and another feature in the data. Run the code block below to produce a scatter matrix.


In [5]:
# Produce a scatter matrix for each pair of features in the data
pd.scatter_matrix(data, alpha = 0.3, figsize = (14,8), diagonal = 'kde');


Question 3

Are there any pairs of features which exhibit some degree of correlation? Does this confirm or deny your suspicions about the relevance of the feature you attempted to predict? How is the data for those features distributed?
Hint: Is the data normally distributed? Where do most of the data points lie?

Answer:

There are pairs of features which exhibit some degree of correlation. For example, Detergents_Paper has a positive correlation with Milk and Grocery respectively. This result agrees with the high R^2 score.

The data is skewed right. Most of the data points are on the left side.

Data Preprocessing

In this section, you will preprocess the data to create a better representation of customers by performing a scaling on the data and detecting (and optionally removing) outliers. Preprocessing data is often times a critical step in assuring that results you obtain from your analysis are significant and meaningful.

Implementation: Feature Scaling

If data is not normally distributed, especially if the mean and median vary significantly (indicating a large skew), it is most often appropriate to apply a non-linear scaling — particularly for financial data. One way to achieve this scaling is by using a Box-Cox test, which calculates the best power transformation of the data that reduces skewness. A simpler approach which can work in most cases would be applying the natural logarithm.

In the code block below, you will need to implement the following:

  • Assign a copy of the data to log_data after applying logarithmic scaling. Use the np.log function for this.
  • Assign a copy of the sample data to log_samples after applying logarithmic scaling. Again, use np.log.

In [6]:
# TODO: Scale the data using the natural logarithm
log_data = data.apply(np.log)

# TODO: Scale the sample data using the natural logarithm
log_samples = samples.apply(np.log)

# Produce a scatter matrix for each pair of newly-transformed features
pd.scatter_matrix(log_data, alpha = 0.3, figsize = (14,8), diagonal = 'kde');


Observation

After applying a natural logarithm scaling to the data, the distribution of each feature should appear much more normal. For any pairs of features you may have identified earlier as being correlated, observe here whether that correlation is still present (and whether it is now stronger or weaker than before).

Run the code below to see how the sample data has changed after having the natural logarithm applied to it.


In [7]:
# Display the log-transformed sample data
display(log_samples)


Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
0 9.483873 7.024649 8.416931 7.258412 6.308098 6.208590
1 9.358243 8.959183 9.404590 8.087025 8.991562 8.015988
2 8.028455 9.490998 10.048756 8.279190 9.206232 6.594413

Implementation: Outlier Detection

Detecting outliers in the data is extremely important in the data preprocessing step of any analysis. The presence of outliers can often skew results which take into consideration these data points. There are many "rules of thumb" for what constitutes an outlier in a dataset. Here, we will use Tukey's Method for identfying outliers: An outlier step is calculated as 1.5 times the interquartile range (IQR). A data point with a feature that is beyond an outlier step outside of the IQR for that feature is considered abnormal.

In the code block below, you will need to implement the following:

  • Assign the value of the 25th percentile for the given feature to Q1. Use np.percentile for this.
  • Assign the value of the 75th percentile for the given feature to Q3. Again, use np.percentile.
  • Assign the calculation of an outlier step for the given feature to step.
  • Optionally remove data points from the dataset by adding indices to the outliers list.

NOTE: If you choose to remove any outliers, ensure that the sample data does not contain any of these points!
Once you have performed this implementation, the dataset will be stored in the variable good_data.


In [8]:
# For each feature find the data points with extreme high or low values

# Returns a dict to hold (feature, outlier_index_list)
def find_outliers():
    feature_outliers = {}
    
    for feature in log_data.keys():
        # TODO: Calculate Q1 (25th percentile of the data) for the given feature
        Q1 = np.percentile(log_data[feature], 25)

        # TODO: Calculate Q3 (75th percentile of the data) for the given feature
        Q3 = np.percentile(log_data[feature], 75)

        # TODO: Use the interquartile range to calculate an outlier step (1.5 times the interquartile range)
        step = 1.5 * (Q3 - Q1)

        # Display the outliers
        print "Data points considered outliers for the feature '{}':".format(feature)
        outlier = ~(log_data[feature] >= Q1 - step) & (log_data[feature] <= Q3 + step)
        display(log_data[outlier])
        outlier_idx = log_data[outlier].index.tolist()
        feature_outliers[feature] = outlier_idx    
    return feature_outliers

# OPTIONAL: Select the indices for data points you wish to remove
# If an index appears more than twice in any features, add it to outliers
outliers_set  = set()
seen = []
feature_outliers = find_outliers()
for k1, v1 in feature_outliers.iteritems():
    for k2, v2 in feature_outliers.iteritems():
        if k1 != k2 and not (k2 in seen):
            same = set(v1).intersection(set(v2))
            if len(same) > 0:
                print('{} are in {} and {}'.format(same, k1, k2))
                outliers_set.update(same)
        seen.append(k1)
outliers  = list(outliers_set)
print('Outlier indexes {} '.format(outliers))

# Remove the outliers, if any were specified
good_data = log_data.drop(log_data.index[outliers]).reset_index(drop = True)


Data points considered outliers for the feature 'Fresh':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
65 4.442651 9.950323 10.732651 3.583519 10.095388 7.260523
66 2.197225 7.335634 8.911530 5.164786 8.151333 3.295837
81 5.389072 9.163249 9.575192 5.645447 8.964184 5.049856
95 1.098612 7.979339 8.740657 6.086775 5.407172 6.563856
96 3.135494 7.869402 9.001839 4.976734 8.262043 5.379897
128 4.941642 9.087834 8.248791 4.955827 6.967909 1.098612
171 5.298317 10.160530 9.894245 6.478510 9.079434 8.740337
193 5.192957 8.156223 9.917982 6.865891 8.633731 6.501290
218 2.890372 8.923191 9.629380 7.158514 8.475746 8.759669
304 5.081404 8.917311 10.117510 6.424869 9.374413 7.787382
305 5.493061 9.468001 9.088399 6.683361 8.271037 5.351858
338 1.098612 5.808142 8.856661 9.655090 2.708050 6.309918
353 4.762174 8.742574 9.961898 5.429346 9.069007 7.013016
355 5.247024 6.588926 7.606885 5.501258 5.214936 4.844187
357 3.610918 7.150701 10.011086 4.919981 8.816853 4.700480
412 4.574711 8.190077 9.425452 4.584967 7.996317 4.127134
Data points considered outliers for the feature 'Milk':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
98 6.220590 4.718499 6.656727 6.796824 4.025352 4.882802
154 6.432940 4.007333 4.919981 4.317488 1.945910 2.079442
356 10.029503 4.897840 5.384495 8.057377 2.197225 6.306275
Data points considered outliers for the feature 'Grocery':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
75 9.923192 7.036148 1.098612 8.390949 1.098612 6.882437
154 6.432940 4.007333 4.919981 4.317488 1.945910 2.079442
Data points considered outliers for the feature 'Frozen':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
38 8.431853 9.663261 9.723703 3.496508 8.847360 6.070738
57 8.597297 9.203618 9.257892 3.637586 8.932213 7.156177
65 4.442651 9.950323 10.732651 3.583519 10.095388 7.260523
145 10.000569 9.034080 10.457143 3.737670 9.440738 8.396155
175 7.759187 8.967632 9.382106 3.951244 8.341887 7.436617
264 6.978214 9.177714 9.645041 4.110874 8.696176 7.142827
420 8.402007 8.569026 9.490015 3.218876 8.827321 7.239215
429 9.060331 7.467371 8.183118 3.850148 4.430817 7.824446
439 7.932721 7.437206 7.828038 4.174387 6.167516 3.951244
Data points considered outliers for the feature 'Detergents_Paper':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
75 9.923192 7.036148 1.098612 8.390949 1.098612 6.882437
161 9.428190 6.291569 5.645447 6.995766 1.098612 7.711101
Data points considered outliers for the feature 'Delicatessen':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
66 2.197225 7.335634 8.911530 5.164786 8.151333 3.295837
109 7.248504 9.724899 10.274568 6.511745 6.728629 1.098612
128 4.941642 9.087834 8.248791 4.955827 6.967909 1.098612
137 8.034955 8.997147 9.021840 6.493754 6.580639 3.583519
142 10.519646 8.875147 9.018332 8.004700 2.995732 1.098612
154 6.432940 4.007333 4.919981 4.317488 1.945910 2.079442
184 5.789960 6.822197 8.457443 4.304065 5.811141 2.397895
187 7.798933 8.987447 9.192075 8.743372 8.148735 1.098612
203 6.368187 6.529419 7.703459 6.150603 6.860664 2.890372
233 6.871091 8.513988 8.106515 6.842683 6.013715 1.945910
285 10.602965 6.461468 8.188689 6.948897 6.077642 2.890372
289 10.663966 5.655992 6.154858 7.235619 3.465736 3.091042
343 7.431892 8.848509 10.177932 7.283448 9.646593 3.610918
set([154]) are in Grocery and Delicatessen
set([75]) are in Grocery and Detergents_Paper
set([154]) are in Grocery and Milk
set([65]) are in Frozen and Fresh
set([128, 66]) are in Delicatessen and Fresh
set([154]) are in Delicatessen and Milk
Outlier indexes [128, 65, 66, 154, 75] 

Question 4

Are there any data points considered outliers for more than one feature based on the definition above? Should these data points be removed from the dataset? If any data points were added to the outliers list to be removed, explain why.

Answer:

There are 5 data points that appears in more than one feature list. These data points should be removed because they don't represent the data well and tend to make the analysis inaccurately.

  • 65 - outlier in Frozen and Fresh
  • 66 - outlier in Delicatessen and Fresh
  • 75 - outlier in Grocery and Detergents_Paper
  • 128 - outlier in Delicatessen and Fresh
  • 154 - outlier in Grocery, Milk, Delicatesse

Feature Transformation

In this section you will use principal component analysis (PCA) to draw conclusions about the underlying structure of the wholesale customer data. Since using PCA on a dataset calculates the dimensions which best maximize variance, we will find which compound combinations of features best describe customers.

Implementation: PCA

Now that the data has been scaled to a more normal distribution and has had any necessary outliers removed, we can now apply PCA to the good_data to discover which dimensions about the data best maximize the variance of features involved. In addition to finding these dimensions, PCA will also report the explained variance ratio of each dimension — how much variance within the data is explained by that dimension alone. Note that a component (dimension) from PCA can be considered a new "feature" of the space, however it is a composition of the original features present in the data.

In the code block below, you will need to implement the following:

  • Import sklearn.decomposition.PCA and assign the results of fitting PCA in six dimensions with good_data to pca.
  • Apply a PCA transformation of log_samples using pca.transform, and assign the results to pca_samples.

In [9]:
from sklearn.decomposition import PCA

# TODO: Apply PCA by fitting the good data with the same number of dimensions as features
pca = PCA(n_components=6)
pca.fit(good_data)

# TODO: Transform log_samples using the PCA fit above
pca_samples = pca.transform(log_samples)

# Generate PCA results plot
pca_results = vs.pca_results(good_data, pca)


Question 5

How much variance in the data is explained in total by the first and second principal component? What about the first four principal components? Using the visualization provided above, discuss what the first four dimensions best represent in terms of customer spending.
Hint: A positive increase in a specific dimension corresponds with an increase of the positive-weighted features and a decrease of the negative-weighted features. The rate of increase or decrease is based on the individual feature weights.


In [10]:
print('First two {}'.format(0.4430 + 0.2638))
print('First four {}'.format(0.4430 + 0.2638 + 0.1231 + 0.1012))


First two 0.7068
First four 0.9311

Answer:

The variance by the first and second PCs is 0.7068 and that by the first four PCs is 0.9311.

  • 1st PC: The customer may be retailer. The spending has large positive weights on Detergents_Paper, Grocery and Milk, small positive weight on Delicatessen and negative weights on Fresh and Frozen.
  • 2nd PC: The customer may be restaurant. The spending has large positive weights on Fresh, Frozen, Delicatesse, small positive weight on the rest.
  • 3rd PC: The customer may be some simple cafeteria that sells delicatessen and frozen food. The spending has large positive weights on Frozen and Delicatessen, small positive weight on Milk, large negative weights on Fresh and small negative weights on Detergents_Paper and Grocery.
  • 4th PC: The customer could be company with its employees work in conditions that mostly consume frozen food. The spending has positive weights on Frozen, small positive weight on Detergents_Paper, Grocery and Milk, large negative weights on Delicatessen and small negative weights on Fresh.

Observation

Run the code below to see how the log-transformed sample data has changed after having a PCA transformation applied to it in six dimensions. Observe the numerical value for the first four dimensions of the sample points. Consider if this is consistent with your initial interpretation of the sample points.


In [11]:
# Display sample log-data after having a PCA transformation applied
display(pd.DataFrame(np.round(pca_samples, 4), columns = pca_results.index.values))


Dimension 1 Dimension 2 Dimension 3 Dimension 4 Dimension 5 Dimension 6
0 -1.0120 0.0103 -0.7516 -0.0545 0.4333 -0.6602
1 2.3579 1.7393 0.2210 0.2840 0.5939 0.0148
2 2.9903 0.3645 0.2521 1.5653 -0.1922 -0.1244

Implementation: Dimensionality Reduction

When using principal component analysis, one of the main goals is to reduce the dimensionality of the data — in effect, reducing the complexity of the problem. Dimensionality reduction comes at a cost: Fewer dimensions used implies less of the total variance in the data is being explained. Because of this, the cumulative explained variance ratio is extremely important for knowing how many dimensions are necessary for the problem. Additionally, if a signifiant amount of variance is explained by only two or three dimensions, the reduced data can be visualized afterwards.

In the code block below, you will need to implement the following:

  • Assign the results of fitting PCA in two dimensions with good_data to pca.
  • Apply a PCA transformation of good_data using pca.transform, and assign the results to reduced_data.
  • Apply a PCA transformation of log_samples using pca.transform, and assign the results to pca_samples.

In [12]:
# TODO: Apply PCA by fitting the good data with only two dimensions
pca = PCA(n_components=2)
pca.fit(good_data)

# TODO: Transform the good data using the PCA fit above
reduced_data = pca.transform(good_data)

# TODO: Transform log_samples using the PCA fit above
pca_samples = pca.transform(log_samples)

# Create a DataFrame for the reduced data
reduced_data = pd.DataFrame(reduced_data, columns = ['Dimension 1', 'Dimension 2'])

Observation

Run the code below to see how the log-transformed sample data has changed after having a PCA transformation applied to it using only two dimensions. Observe how the values for the first two dimensions remains unchanged when compared to a PCA transformation in six dimensions.


In [13]:
# Display sample log-data after applying PCA transformation in two dimensions
display(pd.DataFrame(np.round(pca_samples, 4), columns = ['Dimension 1', 'Dimension 2']))


Dimension 1 Dimension 2
0 -1.0120 0.0103
1 2.3579 1.7393
2 2.9903 0.3645

Visualizing a Biplot

A biplot is a scatterplot where each data point is represented by its scores along the principal components. The axes are the principal components (in this case Dimension 1 and Dimension 2). In addition, the biplot shows the projection of the original features along the components. A biplot can help us interpret the reduced dimensions of the data, and discover relationships between the principal components and original features.

Run the code cell below to produce a biplot of the reduced-dimension data.


In [14]:
# Create a biplot
vs.biplot(good_data, reduced_data, pca)


Out[14]:
<matplotlib.axes._subplots.AxesSubplot at 0x7f98e7d50490>

Observation

Once we have the original feature projections (in red), it is easier to interpret the relative position of each data point in the scatterplot. For instance, a point the lower right corner of the figure will likely correspond to a customer that spends a lot on 'Milk', 'Grocery' and 'Detergents_Paper', but not so much on the other product categories.

From the biplot, which of the original features are most strongly correlated with the first component? What about those that are associated with the second component? Do these observations agree with the pca_results plot you obtained earlier?

Clustering

In this section, you will choose to use either a K-Means clustering algorithm or a Gaussian Mixture Model clustering algorithm to identify the various customer segments hidden in the data. You will then recover specific data points from the clusters to understand their significance by transforming them back into their original dimension and scale.

Question 6

What are the advantages to using a K-Means clustering algorithm? What are the advantages to using a Gaussian Mixture Model clustering algorithm? Given your observations about the wholesale customer data so far, which of the two algorithms will you use and why?

Answer:

Referred to This Answer

K-means

  • The assignment of a cluster is hard, meaning one data point belongs to one cluster
  • Advantages
    • Running Time
    • Better for high dimensional data.
    • Easy to interpret and Implement.
  • Disadvantages
    • Assumes the clusters as spherical, so does not work efficiently with complex geometrical shaped data(Mostly Non-Linear)
    • Hard Assignment might lead to mis grouping.

Gaussian Mixture Model

  • The assignment of a cluster is soft, meaning it uses probability of a sample to determine the feasibility of it belonging to a cluster.
  • Advantages
    • Does not assume clusters to be of any geometry. Works well with non-linear geometric distributions as well.
    • Does not bias the cluster sizes to have specific structures as does by K-Means (Circular).
  • Disadvantages
    • Uses all the components it has access to, so initialization of clusters will be difficult when dimensionality of data is high.
    • Difficult to interpret.

Choice

At the beginning I chose Gaussian Mixture Model because the dimensions aren't high, the shape of the clusters are unknown and hard assignment may not be proper as the customer data showed a mixture of different categories.

But after compared the result of the two models, I found K-Means has better score. Also after compared the result of the hidden variables, I found K-Means is still better. So I guess I'd better choose the simple one to start with.

Implementation: Creating Clusters

Depending on the problem, the number of clusters that you expect to be in the data may already be known. When the number of clusters is not known a priori, there is no guarantee that a given number of clusters best segments the data, since it is unclear what structure exists in the data — if any. However, we can quantify the "goodness" of a clustering by calculating each data point's silhouette coefficient. The silhouette coefficient for a data point measures how similar it is to its assigned cluster from -1 (dissimilar) to 1 (similar). Calculating the mean silhouette coefficient provides for a simple scoring method of a given clustering.

In the code block below, you will need to implement the following:

  • Fit a clustering algorithm to the reduced_data and assign it to clusterer.
  • Predict the cluster for each data point in reduced_data using clusterer.predict and assign them to preds.
  • Find the cluster centers using the algorithm's respective attribute and assign them to centers.
  • Predict the cluster for each sample data point in pca_samples and assign them sample_preds.
  • Import sklearn.metrics.silhouette_score and calculate the silhouette score of reduced_data against preds.
    • Assign the silhouette score to score and print the result.

In [15]:
# TODO: Apply your clustering algorithm of choice to the reduced data
from sklearn.cluster import KMeans
from sklearn.metrics import silhouette_score

def kmeans_clustering(n_classes):
    clusterer = KMeans(n_clusters=n_classes, random_state=0)
    clusterer.fit(reduced_data)

    # TODO: Predict the cluster for each data point
    preds = clusterer.predict(reduced_data)

    # TODO: Find the cluster centers
    centers = clusterer.cluster_centers_

    # TODO: Predict the cluster for each transformed sample data point
    sample_preds = clusterer.predict(pca_samples)

    # TODO: Calculate the mean silhouette coefficient for the number of clusters chosen
    score = silhouette_score(reduced_data, preds, metric='euclidean', random_state=0)
    return (score, reduced_data, preds, centers, pca_samples, sample_preds)

for i in range(2,7):
    score = kmeans_clustering(i)[0]
    print('n_classes={}, score={}'.format(i, score))


n_classes=2, score=0.426281015469
n_classes=3, score=0.39689092645
n_classes=4, score=0.332009582682
n_classes=5, score=0.350990778931
n_classes=6, score=0.366608987343

Question 7

Report the silhouette score for several cluster numbers you tried. Of these, which number of clusters has the best silhouette score?

Answer:

  • n_classes=2, score=0.426281015469
  • n_classes=3, score=0.39689092645
  • n_classes=4, score=0.332009582682
  • n_classes=5, score=0.350990778931
  • n_classes=6, score=0.366608987343

From the above data, the best silhouette score occurs when there are two clusters.

Cluster Visualization

Once you've chosen the optimal number of clusters for your clustering algorithm using the scoring metric above, you can now visualize the results by executing the code block below. Note that, for experimentation purposes, you are welcome to adjust the number of clusters for your clustering algorithm to see various visualizations. The final visualization provided should, however, correspond with the optimal number of clusters.


In [16]:
# Display the results of the clustering from implementation
_, reduced_data, preds, centers, pca_samples, _ = kmeans_clustering(2)
vs.cluster_results(reduced_data, preds, centers, pca_samples)


Extra

I am cusrious at the result of GMM. The result is not as good as KMean.


In [17]:
from sklearn.mixture import GMM
from sklearn.metrics import silhouette_score

def gmm_clustering(n_classes):
    clusterer = GMM(n_components=n_classes, covariance_type='full', random_state=0)
    clusterer.fit(reduced_data)
    preds = clusterer.predict(reduced_data)
    centers = clusterer.means_
    sample_preds = clusterer.predict(pca_samples)
    score = silhouette_score(reduced_data, preds, metric='euclidean', random_state=0)
    return (score, reduced_data, preds, centers, pca_samples, sample_preds)

for i in range(2,7):
    score = gmm_clustering(i)[0]
    print('n_classes={}, score={}'.format(i, score))

_, reduced_data, preds, centers, pca_samples, _ = gmm_clustering(2)
vs.cluster_results(reduced_data, preds, centers, pca_samples)


n_classes=2, score=0.41174985628
n_classes=3, score=0.398431881066
n_classes=4, score=0.291670780284
n_classes=5, score=0.172137581929
n_classes=6, score=0.295416013004

Since the result of K-Means is better, I use the result of K-Mean in the following exercise.


In [18]:
_, reduced_data, preds, centers, pca_samples, sample_preds = kmeans_clustering(2)

Implementation: Data Recovery

Each cluster present in the visualization above has a central point. These centers (or means) are not specifically data points from the data, but rather the averages of all the data points predicted in the respective clusters. For the problem of creating customer segments, a cluster's center point corresponds to the average customer of that segment. Since the data is currently reduced in dimension and scaled by a logarithm, we can recover the representative customer spending from these data points by applying the inverse transformations.

In the code block below, you will need to implement the following:

  • Apply the inverse transform to centers using pca.inverse_transform and assign the new centers to log_centers.
  • Apply the inverse function of np.log to log_centers using np.exp and assign the true centers to true_centers.

In [19]:
# TODO: Inverse transform the centers
log_centers =  pca.inverse_transform(centers)

# TODO: Exponentiate the centers
true_centers = np.exp(log_centers)

# Display the true centers
segments = ['Segment {}'.format(i) for i in range(0,len(centers))]
true_centers = pd.DataFrame(np.round(true_centers), columns = data.keys())
true_centers.index = segments
display(true_centers)


Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
Segment 0 8867.0 1897.0 2477.0 2088.0 294.0 681.0
Segment 1 4005.0 7900.0 12104.0 952.0 4561.0 1036.0

Question 8

Consider the total purchase cost of each product category for the representative data points above, and reference the statistical description of the dataset at the beginning of this project. What set of establishments could each of the customer segments represent?
Hint: A customer who is assigned to 'Cluster X' should best identify with the establishments represented by the feature set of 'Segment X'.

Answer:

  • Segment0: Restaurant. The amount of spending of all categories are lower than the average, meaning the size of the customer isn't big. The customer spends mostly on Fresh, Milk, Grocery and Frozen.

  • Segment1: Retailer. The customer spends more than average on Milk, Grocery, Detergents_Paper, meaning the size of the customer is large. It also spends good amount of Fresh and Delicatessen.

Question 9

For each sample point, which customer segment from Question 8 best represents it? Are the predictions for each sample point consistent with this?

Run the code block below to find which cluster each sample point is predicted to be.


In [20]:
# Display the predictions
for i, pred in enumerate(sample_preds):
    print "Sample point", i, "predicted to be in Cluster", pred


Sample point 0 predicted to be in Cluster 0
Sample point 1 predicted to be in Cluster 1
Sample point 2 predicted to be in Cluster 1

Answer:

  • Sample point 1 Index 11 - Restaurant. The prediction is the same as the assumption.
  • Sample point 2 Index 100 - Retailer. The assumption is market or supermarket which is one kind of retailer.
  • Sample point 3 Index 200 - Retailer. The prediction is the same as the assumption.

Although the last two data points are both retailers, they sell products that focus on different categories.

Conclusion

In this final section, you will investigate ways that you can make use of the clustered data. First, you will consider how the different groups of customers, the customer segments, may be affected differently by a specific delivery scheme. Next, you will consider how giving a label to each customer (which segment that customer belongs to) can provide for additional features about the customer data. Finally, you will compare the customer segments to a hidden variable present in the data, to see whether the clustering identified certain relationships.

Question 10

Companies will often run A/B tests when making small changes to their products or services to determine whether making that change will affect its customers positively or negatively. The wholesale distributor is considering changing its delivery service from currently 5 days a week to 3 days a week. However, the distributor will only make this change in delivery service for customers that react positively. How can the wholesale distributor use the customer segments to determine which customers, if any, would react positively to the change in delivery service?
Hint: Can we assume the change affects all customers equally? How can we determine which group of customers it affects the most?

Answer:

The change will affect customers differently. More frequent delivery is import for customer 1) who spend a lot on Fresh, Milk and Delicatessen; and 2) whose size is small that doesn't stock too much.

For the two segments, the segment 0 will react more positively than segment 1.

In the PCA analysis, the dimension 2 puts more weights on Fresh, Frozen and Delicatessen. We should definitely include this dimension when doing the analysis.

Question 11

Additional structure is derived from originally unlabeled data when using clustering techniques. Since each customer has a customer segment it best identifies with (depending on the clustering algorithm applied), we can consider 'customer segment' as an engineered feature for the data. Assume the wholesale distributor recently acquired ten new customers and each provided estimates for anticipated annual spending of each product category. Knowing these estimates, the wholesale distributor wants to classify each new customer to a customer segment to determine the most appropriate delivery service.
How can the wholesale distributor label the new customers using only their estimated product spending and the customer segment data?
Hint: A supervised learner could be used to train on the original customers. What would be the target variable?

Answer:

The steps of labeling the new customers are as follows.

  1. Data preprocessing: apply natural logrithm to the new customers' data.
  2. Feature transformation: use PCA to transform the preprocessed data.
  3. Classification: use one of the classification methods (Decision Trees, SVN, Logistic Regression...) to predict the label. The target variable is the cluster label. Treat the preprocessed and transformed existing customers' data as the training features and the assigned cluster as the training label. The test features are the data after the first two steps.

Visualizing Underlying Distributions

At the beginning of this project, it was discussed that the 'Channel' and 'Region' features would be excluded from the dataset so that the customer product categories were emphasized in the analysis. By reintroducing the 'Channel' feature to the dataset, an interesting structure emerges when considering the same PCA dimensionality reduction applied earlier to the original dataset.

Run the code block below to see how each data point is labeled either 'HoReCa' (Hotel/Restaurant/Cafe) or 'Retail' the reduced space. In addition, you will find the sample points are circled in the plot, which will identify their labeling.


In [21]:
# Display the clustering results based on 'Channel' data
vs.channel_results(reduced_data, outliers, pca_samples)


Question 12

How well does the clustering algorithm and number of clusters you've chosen compare to this underlying distribution of Hotel/Restaurant/Cafe customers to Retailer customers? Are there customer segments that would be classified as purely 'Retailers' or 'Hotels/Restaurants/Cafes' by this distribution? Would you consider these classifications as consistent with your previous definition of the customer segments?

Answer:

  • The number of the clusters are two which matches what I chosen.
  • The distribution of the data points of the graphs before and after adding the 'Channel' and 'Region' features are somewhat different. Some datapoints overlapped in the two clusters in the underlying distributions while there is almost no overlap in my analysis. But there still are many data points located away from the overlapping area that could be classified as purely 'Retailers' or 'Hotels/Restaurants/Cafes'.
  • The result is mostly consistent with my previoius definition of the customer segments. For example, sample point 2 and 3 have the same label. But sample point 1 is miss classified which located in the heart of cluster 1 but labelled as cluster 2 in the underlying distribution.

Note: Once you have completed all of the code implementations and successfully answered each question above, you may finalize your work by exporting the iPython Notebook as an HTML document. You can do this by using the menu above and navigating to
File -> Download as -> HTML (.html). Include the finished document along with this notebook as your submission.