

In [59]:

    
m = 0.3
rho = 1.225
b = 1.7
s = 0.06
g = 9.8

From Pennycuick(1990), we can predict the wingbeat frequency of an equivalent bird with the equation:

$$ f = 1.08 m^{1/3} g^{1/2} b^{-1} S^{-1/4} \rho^{-1/3} $$

And we can predict the minimum power/ maximum range speed as:

$$ V = m^{1/2} g^{1/2} b^{-1} \rho^{-1/2} $$



In [39]:

    
f = 1.08*m**(1.0/3)*g**(1.0/2)*b**(-1)*s**(-1.0/4)*rho**(-1.0/3)
f









    Out[39]:





2.514076265424935



In [38]:

    
v = 4.77*(m*1.0e3)**(1.0/6)
v









    Out[38]:





12.341612929404564



In [58]:

    
lam = m**(1.0/6)*s**(1.0/4)*rho**(-1.0/6)
lam









    Out[58]:





0.39147317389350833



In [41]:

    
lam = v/f
lam









    Out[41]:





4.909004988883484



In [57]:

    
2/lam









    Out[57]:





5.1089069018661695



In [ ]:

    
lam

Birds, have higher Reynold's number (Re), bodies smooth to fly with laminar flow.



In [ ]: