To answer this question, you'll need to use Bayes' Theorem. Recall:
$$ P(A | B) = \frac{P(B | A) * P(A)}{P(B)} $$We'll call event A "it rains", and event B "the weatherman forecasts rain." What is $P(A | B)$, or the probability of rain given that the weatherman has predicted rain?
Hint: You can rewrite $P(B)$ using the chain rule of probability to be: $P(B | A ) * P(A) + P(B | !A) * P(!A)$, where ! means "negation", or the opposite.
In addition to the final answer, please include your thought process. And please don't consult Google.