In this notebook, you will use LASSO to select features, building on a pre-implemented solver for LASSO (using GraphLab Create, though you can use other solvers). You will:
In the second notebook, you will implement your own LASSO solver, using coordinate descent.
In [1]:
import graphlab
In [2]:
sales = graphlab.SFrame('kc_house_data.gl/')
As in Week 2, we consider features that are some transformations of inputs.
In [3]:
from math import log, sqrt
sales['sqft_living_sqrt'] = sales['sqft_living'].apply(sqrt)
sales['sqft_lot_sqrt'] = sales['sqft_lot'].apply(sqrt)
sales['bedrooms_square'] = sales['bedrooms']*sales['bedrooms']
# In the dataset, 'floors' was defined with type string,
# so we'll convert them to int, before creating a new feature.
sales['floors'] = sales['floors'].astype(int)
sales['floors_square'] = sales['floors']*sales['floors']
Let us fit a model with all the features available, plus the features we just created above.
In [112]:
all_features = ['bedrooms', 'bedrooms_square',
'bathrooms',
'sqft_living', 'sqft_living_sqrt',
'sqft_lot', 'sqft_lot_sqrt',
'floors', 'floors_square',
'waterfront', 'view', 'condition', 'grade',
'sqft_above',
'sqft_basement',
'yr_built', 'yr_renovated']
len(all_features)
Out[112]:
Applying L1 penalty requires adding an extra parameter (l1_penalty) to the linear regression call in GraphLab Create. (Other tools may have separate implementations of LASSO.) Note that it's important to set l2_penalty=0 to ensure we don't introduce an additional L2 penalty.
In [7]:
model_all = graphlab.linear_regression.create(sales, target='price', features=all_features,
validation_set=None,
l2_penalty=0., l1_penalty=1e10, verbose=False)
Find what features had non-zero weight.
In [10]:
model_all.get('coefficients').print_rows(num_rows=len(all_features) + 1)
Note that a majority of the weights have been set to zero. So by setting an L1 penalty that's large enough, we are performing a subset selection.
QUIZ QUESTION: According to this list of weights, which of the features have been chosen?
To find a good L1 penalty, we will explore multiple values using a validation set. Let us do three way split into train, validation, and test sets:
Be very careful that you use seed = 1 to ensure you get the same answer!
In [89]:
(training_and_validation, testing) = sales.random_split(.9,seed=1) # initial train/test split
(training, validation) = training_and_validation.random_split(0.5, seed=1) # split training into train and validate
Next, we write a loop that does the following:
l1_penalty in [10^1, 10^1.5, 10^2, 10^2.5, ..., 10^7] (to get this in Python, type np.logspace(1, 7, num=13).)l1_penalty on TRAIN data. Specify l1_penalty=l1_penalty and l2_penalty=0. in the parameter list..predict()) for that l1_penaltyl1_penalty produced the lowest RSS on validation data.When you call linear_regression.create() make sure you set validation_set = None.
Note: you can turn off the print out of linear_regression.create() with verbose = False
In [114]:
import numpy as np
l1_penalty_list = np.logspace(1, 7, num=13)
sort_table = []
for l1_penalty in l1_penalty_list:
model = graphlab.linear_regression.create(training, target='price', features=all_features,
validation_set=None,
l2_penalty=0, l1_penalty=l1_penalty, verbose=False)
predictions = model.predict(validation)
RSS = sum([(predictions[i] - validation[i]['price']) ** 2 for i in range(len(predictions))])
print l1_penalty, RSS
sort_table.append((RSS, l1_penalty))
print sorted(sort_table)[0]
QUIZ QUESTIONS
l1_penalty?l1_penalty?
In [129]:
best_model = graphlab.linear_regression.create(training, target='price', features=all_features,
validation_set=None,
l2_penalty=0, l1_penalty=10, verbose=False)
best_model.get('coefficients').print_rows(num_rows=len(all_features) + 1)
In [130]:
predictions = best_model.predict(testing)
RSS = sum([(predictions[i] - testing[i]['price']) ** 2 for i in range(len(predictions))])
print RSS
In [132]:
best_model['coefficients']['value'].nnz()
Out[132]:
QUIZ QUESTION Also, using this value of L1 penalty, how many nonzero weights do you have?
In this section, you are going to implement a simple, two phase procedure to achive this goal:
l1_penalty values to find a narrow region of l1_penalty values where models are likely to have the desired number of non-zero weights.l1_penalty that achieves the desired sparsity. Here, we will again use a validation set to choose the best value for l1_penalty.
In [115]:
max_nonzeros = 7
In [116]:
l1_penalty_values = np.logspace(8, 10, num=20)
Now, implement a loop that search through this space of possible l1_penalty values:
l1_penalty in np.logspace(8, 10, num=20):l1_penalty on TRAIN data. Specify l1_penalty=l1_penalty and l2_penalty=0. in the parameter list. When you call linear_regression.create() make sure you set validation_set = Nonemodel['coefficients']['value'] gives you an SArray with the parameters you learned. If you call the method .nnz() on it, you will find the number of non-zero parameters!
In [117]:
info = []
for l1_penalty in l1_penalty_values:
model = graphlab.linear_regression.create(training, target='price', features=all_features,
validation_set=None,
l2_penalty=0, l1_penalty=l1_penalty, verbose=False)
nnz = model['coefficients']['value'].nnz()
info.append((l1_penalty, nnz))
In [120]:
for x in enumerate(info):
print x
Out of this large range, we want to find the two ends of our desired narrow range of l1_penalty. At one end, we will have l1_penalty values that have too few non-zeros, and at the other end, we will have an l1_penalty that has too many non-zeros.
More formally, find:
l1_penalty that has more non-zeros than max_nonzero (if we pick a penalty smaller than this value, we will definitely have too many non-zero weights)l1_penalty_min (we will use it later)l1_penalty that has fewer non-zeros than max_nonzero (if we pick a penalty larger than this value, we will definitely have too few non-zero weights)l1_penalty_max (we will use it later)Hint: there are many ways to do this, e.g.:
l1_penalty and inspecting it to find the appropriate boundaries.
In [122]:
l1_penalty_min = l1_penalty_values[14]
l1_penalty_max = l1_penalty_values[15]
print l1_penalty_min, l1_penalty_max
QUIZ QUESTIONS
What values did you find for l1_penalty_min andl1_penalty_max?
In [124]:
l1_penalty_values = np.linspace(l1_penalty_min,l1_penalty_max,20)
print l1_penalty_values
l1_penalty in np.linspace(l1_penalty_min,l1_penalty_max,20):l1_penalty on TRAIN data. Specify l1_penalty=l1_penalty and l2_penalty=0. in the parameter list. When you call linear_regression.create() make sure you set validation_set = NoneFind the model that the lowest RSS on the VALIDATION set and has sparsity equal to max_nonzero.
In [126]:
sort_table = []
for l1_penalty in l1_penalty_values:
model = graphlab.linear_regression.create(training, target='price', features=all_features,
validation_set=None,
l2_penalty=0, l1_penalty=l1_penalty, verbose=False)
nnz = model['coefficients']['value'].nnz()
if not nnz == max_nonzeros:
continue
predictions = model.predict(validation)
RSS = sum([(predictions[i] - validation[i]['price']) ** 2 for i in range(len(predictions))])
print l1_penalty, RSS
sort_table.append((RSS, l1_penalty))
print sorted(sort_table)[0]
QUIZ QUESTIONS
l1_penalty in our narrow range has the lowest RSS on the VALIDATION set and has sparsity equal to max_nonzeros?
In [128]:
best_model = graphlab.linear_regression.create(training, target='price', features=all_features,
validation_set=None,
l2_penalty=0, l1_penalty=3320073020.20013, verbose=False)
best_model.get('coefficients').print_rows(num_rows=len(all_features) + 1)