Machine Learning Engineer Nanodegree

Unsupervised Learning

Project: Creating Customer Segments

Welcome to the third project of the Machine Learning Engineer Nanodegree! In this notebook, some template code has already been provided for you, and it will be your job to implement the additional functionality necessary to successfully complete this project. Sections that begin with 'Implementation' in the header indicate that the following block of code will require additional functionality which you must provide. Instructions will be provided for each section and the specifics of the implementation are marked in the code block with a 'TODO' statement. Please be sure to read the instructions carefully!

In addition to implementing code, there will be questions that you must answer which relate to the project and your implementation. Each section where you will answer a question is preceded by a 'Question X' header. Carefully read each question and provide thorough answers in the following text boxes that begin with 'Answer:'. Your project submission will be evaluated based on your answers to each of the questions and the implementation you provide.

Note: Code and Markdown cells can be executed using the Shift + Enter keyboard shortcut. In addition, Markdown cells can be edited by typically double-clicking the cell to enter edit mode.

Getting Started

In this project, you will analyze a dataset containing data on various customers' annual spending amounts (reported in monetary units) of diverse product categories for internal structure. One goal of this project is to best describe the variation in the different types of customers that a wholesale distributor interacts with. Doing so would equip the distributor with insight into how to best structure their delivery service to meet the needs of each customer.

The dataset for this project can be found on the UCI Machine Learning Repository. For the purposes of this project, the features 'Channel' and 'Region' will be excluded in the analysis — with focus instead on the six product categories recorded for customers.

Run the code block below to load the wholesale customers dataset, along with a few of the necessary Python libraries required for this project. You will know the dataset loaded successfully if the size of the dataset is reported.


In [1]:
# Import libraries necessary for this project
import numpy as np
import pandas as pd
from IPython.display import display # Allows the use of display() for DataFrames

# Import supplementary visualizations code visuals.py
import visuals as vs

# Pretty display for notebooks
%matplotlib inline

# Load the wholesale customers dataset
try:
    data = pd.read_csv("customers.csv")
    data.drop(['Region', 'Channel'], axis = 1, inplace = True)
    print "Wholesale customers dataset has {} samples with {} features each.".format(*data.shape)
except:
    print "Dataset could not be loaded. Is the dataset missing?"


Wholesale customers dataset has 440 samples with 6 features each.

Data Exploration

In this section, you will begin exploring the data through visualizations and code to understand how each feature is related to the others. You will observe a statistical description of the dataset, consider the relevance of each feature, and select a few sample data points from the dataset which you will track through the course of this project.

Run the code block below to observe a statistical description of the dataset. Note that the dataset is composed of six important product categories: 'Fresh', 'Milk', 'Grocery', 'Frozen', 'Detergents_Paper', and 'Delicatessen'. Consider what each category represents in terms of products you could purchase.


In [2]:
# Display a description of the dataset
display(data.describe())


Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
count 440.000000 440.000000 440.000000 440.000000 440.000000 440.000000
mean 12000.297727 5796.265909 7951.277273 3071.931818 2881.493182 1524.870455
std 12647.328865 7380.377175 9503.162829 4854.673333 4767.854448 2820.105937
min 3.000000 55.000000 3.000000 25.000000 3.000000 3.000000
25% 3127.750000 1533.000000 2153.000000 742.250000 256.750000 408.250000
50% 8504.000000 3627.000000 4755.500000 1526.000000 816.500000 965.500000
75% 16933.750000 7190.250000 10655.750000 3554.250000 3922.000000 1820.250000
max 112151.000000 73498.000000 92780.000000 60869.000000 40827.000000 47943.000000

Implementation: Selecting Samples

To get a better understanding of the customers and how their data will transform through the analysis, it would be best to select a few sample data points and explore them in more detail. In the code block below, add three indices of your choice to the indices list which will represent the customers to track. It is suggested to try different sets of samples until you obtain customers that vary significantly from one another.


In [3]:
# TODO: Select three indices of your choice you wish to sample from the dataset
indices = [201,47,399]

# Create a DataFrame of the chosen samples
samples = pd.DataFrame(data.loc[indices], columns = data.keys()).reset_index(drop = True)
print "Chosen samples of wholesale customers dataset:"
display(samples)

print "Chosen samples offset from mean:"
display(samples - np.around(data.mean().values))

print "Chosen samples offset from median:"
display(samples - np.around(data.median().values))


Chosen samples of wholesale customers dataset:
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
0 4484 14399 24708 3549 14235 1681
1 44466 54259 55571 7782 24171 6465
2 9612 577 935 1601 469 375
Chosen samples offset from mean:
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
0 -7516.0 8603.0 16757.0 477.0 11354.0 156.0
1 32466.0 48463.0 47620.0 4710.0 21290.0 4940.0
2 -2388.0 -5219.0 -7016.0 -1471.0 -2412.0 -1150.0
Chosen samples offset from median:
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
0 -4020.0 10772.0 19952.0 2023.0 13419.0 715.0
1 35962.0 50632.0 50815.0 6256.0 23355.0 5499.0
2 1108.0 -3050.0 -3821.0 75.0 -347.0 -591.0

Question 1

Consider the total purchase cost of each product category and the statistical description of the dataset above for your sample customers.
What kind of establishment (customer) could each of the three samples you've chosen represent?
Hint: Examples of establishments include places like markets, cafes, and retailers, among many others. Avoid using names for establishments, such as saying "McDonalds" when describing a sample customer as a restaurant.

Answer:

  1. Bakery and Pastries restaurant.- Due to the consumption of milk, grocery and delicatessen we can observe that this product are bought in order to build all the necessary elements of the pastries and baked goods. In terms of detergents and paper, their consumption is also fairly high due to the number of customers and the required elements to clean the kitchen.
  2. Market Place.- The high consumptions in all products, most of them above the mean, indicates that the customer buy all this products in order to re-sell them in their local market.
  3. Coffee place, the small number of offered products is reduced, however as a coffee place the demand for fresh, milk and frozen products is high. Also since most people order their product and leave afterwards, the consumptions in detergents and paper is low.

Implementation: Feature Relevance

One interesting thought to consider is if one (or more) of the six product categories is actually relevant for understanding customer purchasing. That is to say, is it possible to determine whether customers purchasing some amount of one category of products will necessarily purchase some proportional amount of another category of products? We can make this determination quite easily by training a supervised regression learner on a subset of the data with one feature removed, and then score how well that model can predict the removed feature.

In the code block below, you will need to implement the following:

  • Assign new_data a copy of the data by removing a feature of your choice using the DataFrame.drop function.
  • Use sklearn.cross_validation.train_test_split to split the dataset into training and testing sets.
    • Use the removed feature as your target label. Set a test_size of 0.25 and set a random_state.
  • Import a decision tree regressor, set a random_state, and fit the learner to the training data.
  • Report the prediction score of the testing set using the regressor's score function.

In [4]:
# TODO: Make a copy of the DataFrame, using the 'drop' function to drop the given feature
categories = ['Fresh', 'Milk', 'Grocery', 'Frozen', 'Detergents_Paper', 'Delicatessen']
for cat in categories:
    
    # TODO: Make a copy of the DataFrame, using the 'drop' function to drop the given feature
    y = data[cat]
    new_data = data.drop([cat], axis = 1)

    # TODO: Split the data into training and testing sets using the given feature as the target
    from sklearn.cross_validation import train_test_split
    X_train, X_test, y_train, y_test = train_test_split(new_data, y, test_size = 0.25, random_state = 1)

    # TODO: Create a decision tree regressor and fit it to the training set
    from sklearn.tree import DecisionTreeRegressor
    regressor = DecisionTreeRegressor(random_state = 1)
    regressor.fit(X_train, y_train)


    # TODO: Report the score of the prediction using the testing set
    score = regressor.score(X_test, y_test)
    print 'Score of {} is {:.3f}'.format(cat, score)


Score of Fresh is -0.923
Score of Milk is 0.516
Score of Grocery is 0.796
Score of Frozen is -0.650
Score of Detergents_Paper is 0.815
Score of Delicatessen is -0.429

Question 2

Which feature did you attempt to predict? What was the reported prediction score? Is this feature is necessary for identifying customers' spending habits?
Hint: The coefficient of determination, R^2, is scored between 0 and 1, with 1 being a perfect fit. A negative R^2 implies the model fails to fit the data.

Answer:

Well, since I am curiuous I predicted all of them with the following results in descendent order. A high R^2 implies that a feature is contained at a certain degree in the other features, making it irrelevant.

  1. Not relevant:
    • Detergents_Paper
    • Grocery
    • Milk
  2. Relevant(all the elements fail to be predicted):
    • Delicatessen
    • Frozen
    • Fresh

Visualize Feature Distributions

To get a better understanding of the dataset, we can construct a scatter matrix of each of the six product features present in the data. If you found that the feature you attempted to predict above is relevant for identifying a specific customer, then the scatter matrix below may not show any correlation between that feature and the others. Conversely, if you believe that feature is not relevant for identifying a specific customer, the scatter matrix might show a correlation between that feature and another feature in the data. Run the code block below to produce a scatter matrix.


In [5]:
# Produce a scatter matrix for each pair of features in the data
pd.scatter_matrix(data, alpha = 0.3, figsize = (14,8), diagonal = 'kde');


Question 3

Are there any pairs of features which exhibit some degree of correlation? Does this confirm or deny your suspicions about the relevance of the feature you attempted to predict? How is the data for those features distributed?
Hint: Is the data normally distributed? Where do most of the data points lie?

Answer:

We can see a correlation between all of the three categories previously stated: Milk, Grocery and Detergents. Confirming the assumptions stated above.

The data is all clearly skewed to the right, so the data is not normally distributed.

Data Preprocessing

In this section, you will preprocess the data to create a better representation of customers by performing a scaling on the data and detecting (and optionally removing) outliers. Preprocessing data is often times a critical step in assuring that results you obtain from your analysis are significant and meaningful.

Implementation: Feature Scaling

If data is not normally distributed, especially if the mean and median vary significantly (indicating a large skew), it is most often appropriate to apply a non-linear scaling — particularly for financial data. One way to achieve this scaling is by using a Box-Cox test, which calculates the best power transformation of the data that reduces skewness. A simpler approach which can work in most cases would be applying the natural logarithm.

In the code block below, you will need to implement the following:

  • Assign a copy of the data to log_data after applying logarithmic scaling. Use the np.log function for this.
  • Assign a copy of the sample data to log_samples after applying logarithmic scaling. Again, use np.log.

In [6]:
# TODO: Scale the data using the natural logarithm
log_data = np.log(data)

# TODO: Scale the sample data using the natural logarithm
log_samples = np.log(samples)

# Produce a scatter matrix for each pair of newly-transformed features
pd.scatter_matrix(log_data, alpha = 0.3, figsize = (14,8), diagonal = 'kde');

display(log_data.describe())


Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
count 440.000000 440.000000 440.000000 440.000000 440.000000 440.000000
mean 8.730544 8.121047 8.441169 7.301396 6.785972 6.665133
std 1.480071 1.081365 1.116172 1.284540 1.721020 1.310832
min 1.098612 4.007333 1.098612 3.218876 1.098612 1.098612
25% 8.048059 7.334981 7.674616 6.609678 5.548101 6.011875
50% 9.048286 8.196159 8.467057 7.330388 6.705018 6.872645
75% 9.737064 8.880480 9.273854 8.175896 8.274341 7.506728
max 11.627601 11.205013 11.437986 11.016479 10.617099 10.777768

Observation

After applying a natural logarithm scaling to the data, the distribution of each feature should appear much more normal. For any pairs of features you may have identified earlier as being correlated, observe here whether that correlation is still present (and whether it is now stronger or weaker than before).

Run the code below to see how the sample data has changed after having the natural logarithm applied to it.


In [7]:
# Display the log-transformed sample data
display(log_samples)


Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
0 8.408271 9.574914 10.114882 8.174421 9.563459 7.427144
1 10.702480 10.901524 10.925417 8.959569 10.092909 8.774158
2 9.170768 6.357842 6.840547 7.378384 6.150603 5.926926

Implementation: Outlier Detection

Detecting outliers in the data is extremely important in the data preprocessing step of any analysis. The presence of outliers can often skew results which take into consideration these data points. There are many "rules of thumb" for what constitutes an outlier in a dataset. Here, we will use Tukey's Method for identfying outliers: An outlier step is calculated as 1.5 times the interquartile range (IQR). A data point with a feature that is beyond an outlier step outside of the IQR for that feature is considered abnormal.

In the code block below, you will need to implement the following:

  • Assign the value of the 25th percentile for the given feature to Q1. Use np.percentile for this.
  • Assign the value of the 75th percentile for the given feature to Q3. Again, use np.percentile.
  • Assign the calculation of an outlier step for the given feature to step.
  • Optionally remove data points from the dataset by adding indices to the outliers list.

NOTE: If you choose to remove any outliers, ensure that the sample data does not contain any of these points!
Once you have performed this implementation, the dataset will be stored in the variable good_data.


In [21]:
# For each feature find the data points with extreme high or low values

repeated_index = {}

for feature in log_data.keys():
    
    # TODO: Calculate Q1 (25th percentile of the data) for the given feature
    Q1 = np.percentile(log_data[feature], 25)
    
    # TODO: Calculate Q3 (75th percentile of the data) for the given feature
    Q3 = np.percentile(log_data[feature], 75)
    
    # TODO: Use the interquartile range to calculate an outlier step (1.5 times the interquartile range)
    step = (Q3 - Q1) * 1.5
    
    # Display the outliers
    print "Data points considered outliers for the feature '{}':".format(feature)
    display(log_data[~((log_data[feature] >= Q1 - step) & (log_data[feature] <= Q3 + step))])
    # Check the index that are repeated more than once
    for i in log_data[~((log_data[feature] >= Q1 - step) & (log_data[feature] <= Q3 + step))].index:
        if i not in repeated_index:
            repeated_index[i] = 1
        else:
            repeated_index[i] += 1
    
# OPTIONAL: Select the indices for data points you wish to remove

outliers  = []
for key in repeated_index.keys():
    if repeated_index[key] > 1:
        outliers.append(key)
print 'Outliners represented in 2 or more features: {}'.format(outliers)

outliers += [154, 95, 328, 75, 420, 142, 187, 86, 183, 325]

# Min 1.098612	4.007333	1.098612	3.218876	1.098612	1.098612
# Max 11.627601	11.205013	11.437986	11.016479	10.617099	10.777768

# Remove the outliers, if any were specified
print 'All Outliers: {}'.format(outliers)
good_data = log_data.drop(log_data.index[outliers]).reset_index(drop = True)


Data points considered outliers for the feature 'Fresh':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
65 4.442651 9.950323 10.732651 3.583519 10.095388 7.260523
66 2.197225 7.335634 8.911530 5.164786 8.151333 3.295837
81 5.389072 9.163249 9.575192 5.645447 8.964184 5.049856
95 1.098612 7.979339 8.740657 6.086775 5.407172 6.563856
96 3.135494 7.869402 9.001839 4.976734 8.262043 5.379897
128 4.941642 9.087834 8.248791 4.955827 6.967909 1.098612
171 5.298317 10.160530 9.894245 6.478510 9.079434 8.740337
193 5.192957 8.156223 9.917982 6.865891 8.633731 6.501290
218 2.890372 8.923191 9.629380 7.158514 8.475746 8.759669
304 5.081404 8.917311 10.117510 6.424869 9.374413 7.787382
305 5.493061 9.468001 9.088399 6.683361 8.271037 5.351858
338 1.098612 5.808142 8.856661 9.655090 2.708050 6.309918
353 4.762174 8.742574 9.961898 5.429346 9.069007 7.013016
355 5.247024 6.588926 7.606885 5.501258 5.214936 4.844187
357 3.610918 7.150701 10.011086 4.919981 8.816853 4.700480
412 4.574711 8.190077 9.425452 4.584967 7.996317 4.127134
Data points considered outliers for the feature 'Milk':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
86 10.039983 11.205013 10.377047 6.894670 9.906981 6.805723
98 6.220590 4.718499 6.656727 6.796824 4.025352 4.882802
154 6.432940 4.007333 4.919981 4.317488 1.945910 2.079442
356 10.029503 4.897840 5.384495 8.057377 2.197225 6.306275
Data points considered outliers for the feature 'Grocery':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
75 9.923192 7.036148 1.098612 8.390949 1.098612 6.882437
154 6.432940 4.007333 4.919981 4.317488 1.945910 2.079442
Data points considered outliers for the feature 'Frozen':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
38 8.431853 9.663261 9.723703 3.496508 8.847360 6.070738
57 8.597297 9.203618 9.257892 3.637586 8.932213 7.156177
65 4.442651 9.950323 10.732651 3.583519 10.095388 7.260523
145 10.000569 9.034080 10.457143 3.737670 9.440738 8.396155
175 7.759187 8.967632 9.382106 3.951244 8.341887 7.436617
264 6.978214 9.177714 9.645041 4.110874 8.696176 7.142827
325 10.395650 9.728181 9.519735 11.016479 7.148346 8.632128
420 8.402007 8.569026 9.490015 3.218876 8.827321 7.239215
429 9.060331 7.467371 8.183118 3.850148 4.430817 7.824446
439 7.932721 7.437206 7.828038 4.174387 6.167516 3.951244
Data points considered outliers for the feature 'Detergents_Paper':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
75 9.923192 7.036148 1.098612 8.390949 1.098612 6.882437
161 9.428190 6.291569 5.645447 6.995766 1.098612 7.711101
Data points considered outliers for the feature 'Delicatessen':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
66 2.197225 7.335634 8.911530 5.164786 8.151333 3.295837
109 7.248504 9.724899 10.274568 6.511745 6.728629 1.098612
128 4.941642 9.087834 8.248791 4.955827 6.967909 1.098612
137 8.034955 8.997147 9.021840 6.493754 6.580639 3.583519
142 10.519646 8.875147 9.018332 8.004700 2.995732 1.098612
154 6.432940 4.007333 4.919981 4.317488 1.945910 2.079442
183 10.514529 10.690808 9.911952 10.505999 5.476464 10.777768
184 5.789960 6.822197 8.457443 4.304065 5.811141 2.397895
187 7.798933 8.987447 9.192075 8.743372 8.148735 1.098612
203 6.368187 6.529419 7.703459 6.150603 6.860664 2.890372
233 6.871091 8.513988 8.106515 6.842683 6.013715 1.945910
285 10.602965 6.461468 8.188689 6.948897 6.077642 2.890372
289 10.663966 5.655992 6.154858 7.235619 3.465736 3.091042
343 7.431892 8.848509 10.177932 7.283448 9.646593 3.610918
Outliners represented in 2 or more features: [128, 154, 65, 66, 75]
All Outliers: [128, 154, 65, 66, 75, 154, 95, 328, 75, 420, 142, 187, 86, 183, 325]

Question 4

Are there any data points considered outliers for more than one feature based on the definition above? Should these data points be removed from the dataset? If any data points were added to the outliers list to be removed, explain why.

Answer:

The data points _65, 66, 75, 128, 154_ are repeated more than once in the dataset, hence they should be removed from the dataset due to them affecting more than one entry point. It has a greater damage than those that only affect one.
Points being removed for being the min in their category:
- _Data Point 161_.- Value of 1.098612. Feature Detergents_Paper.
- _Data Point 95, 338.- Min element for Fresh (1.098612).
- _Data Point 154_.- Min element for Milk (4.007333)
- _Data Point 75_.- Grocery (1.098612)
- _Data Point 420_.- Frozen (3.218876)
- _Data Point 142, 187_.- Delicatessen (3.218876)

Points being removed for being the max in their category:
- _Data Point 86_.- Min element for Milk (11.205013)
- _Data Point 325_.- Frozen (11.016479)
- _Data Point 183_.- Delicatessen (10.777768)

A simple procedure for deleting outliers was placed, deleted the min and max elements in the dataset __that are considered outliers__ and delete those who are present in more than one category. 

Feature Transformation

In this section you will use principal component analysis (PCA) to draw conclusions about the underlying structure of the wholesale customer data. Since using PCA on a dataset calculates the dimensions which best maximize variance, we will find which compound combinations of features best describe customers.

Implementation: PCA

Now that the data has been scaled to a more normal distribution and has had any necessary outliers removed, we can now apply PCA to the good_data to discover which dimensions about the data best maximize the variance of features involved. In addition to finding these dimensions, PCA will also report the explained variance ratio of each dimension — how much variance within the data is explained by that dimension alone. Note that a component (dimension) from PCA can be considered a new "feature" of the space, however it is a composition of the original features present in the data.

In the code block below, you will need to implement the following:

  • Import sklearn.decomposition.PCA and assign the results of fitting PCA in six dimensions with good_data to pca.
  • Apply a PCA transformation of log_samples using pca.transform, and assign the results to pca_samples.

In [9]:
# TODO: Apply PCA by fitting the good data with the same number of dimensions as features
from sklearn.decomposition import PCA
pca = PCA(n_components=6).fit(good_data)

# TODO: Transform log_samples using the PCA fit above
pca_samples = pca.transform(log_samples)

# Generate PCA results plot
pca_results = vs.pca_results(good_data, pca)


Question 5

How much variance in the data is explained in total by the first and second principal component? What about the first four principal components? Using the visualization provided above, discuss what the first four dimensions best represent in terms of customer spending.
Hint: A positive increase in a specific dimension corresponds with an increase of the positive-weighted features and a decrease of the negative-weighted features. The rate of increase or decrease is based on the indivdual feature weights.


In [10]:
print pca_results['Explained Variance'].cumsum()


Dimension 1    0.4607
Dimension 2    0.7180
Dimension 3    0.8356
Dimension 4    0.9335
Dimension 5    0.9786
Dimension 6    1.0000
Name: Explained Variance, dtype: float64

Answer:

The variance for the first two columns equals 71.80%. The first four components equate for 93.35% of the variance.

In terms of each specific dimension:

  • First dimension is meaningful weighted towards Milk, Grocery and heavily weighted towards Detergents. This dimension is best categorized by retail goods customers.
  • Second dimension, we can observe how the components greatly switch, by now relying especially on Fresh, with also an emphasis in Delicatessen and Frozen. This dimension is best categorized by restaurant customers.
  • Third dimension Frozen and Delicatessen remain constant with respect to the second one. However, the component of Fresh has a heavily negative weight. Milk also has a positive weight. I believe this dimension is better represented by customers that sell coffee and icecream.
  • Fourth dimension the model is high on Delicatessen and a particular low weight in Frozen products. This dimension would be best represented by a candy shop or a bakery.

Observation

Run the code below to see how the log-transformed sample data has changed after having a PCA transformation applied to it in six dimensions. Observe the numerical value for the first four dimensions of the sample points. Consider if this is consistent with your initial interpretation of the sample points.


In [11]:
# Display sample log-data after having a PCA transformation applied
display(pd.DataFrame(np.round(pca_samples, 4), columns = pca_results.index.values))


Dimension 1 Dimension 2 Dimension 3 Dimension 4 Dimension 5 Dimension 6
0 3.4154 1.0390 0.5960 -0.9264 0.0107 0.0873
1 4.3697 3.9711 0.0133 -0.5295 -0.6101 0.0575
2 -2.0911 -0.5083 -0.6284 -0.3890 1.2527 -0.2845

Implementation: Dimensionality Reduction

When using principal component analysis, one of the main goals is to reduce the dimensionality of the data — in effect, reducing the complexity of the problem. Dimensionality reduction comes at a cost: Fewer dimensions used implies less of the total variance in the data is being explained. Because of this, the cumulative explained variance ratio is extremely important for knowing how many dimensions are necessary for the problem. Additionally, if a signifiant amount of variance is explained by only two or three dimensions, the reduced data can be visualized afterwards.

In the code block below, you will need to implement the following:

  • Assign the results of fitting PCA in two dimensions with good_data to pca.
  • Apply a PCA transformation of good_data using pca.transform, and assign the results to reduced_data.
  • Apply a PCA transformation of log_samples using pca.transform, and assign the results to pca_samples.

In [12]:
# TODO: Apply PCA by fitting the good data with only two dimensions
pca = PCA(n_components=2).fit(good_data)

# TODO: Transform the good data using the PCA fit above
reduced_data = pca.transform(good_data)

# TODO: Transform log_samples using the PCA fit above
pca_samples = pca.transform(log_samples)

# Create a DataFrame for the reduced data
reduced_data = pd.DataFrame(reduced_data, columns = ['Dimension 1', 'Dimension 2'])
print 'done'


done

Observation

Run the code below to see how the log-transformed sample data has changed after having a PCA transformation applied to it using only two dimensions. Observe how the values for the first two dimensions remains unchanged when compared to a PCA transformation in six dimensions.


In [13]:
# Display sample log-data after applying PCA transformation in two dimensions
display(pd.DataFrame(np.round(pca_samples, 4), columns = ['Dimension 1', 'Dimension 2']))


Dimension 1 Dimension 2
0 3.4154 1.0390
1 4.3697 3.9711
2 -2.0911 -0.5083

Visualizing a Biplot

A biplot is a scatterplot where each data point is represented by its scores along the principal components. The axes are the principal components (in this case Dimension 1 and Dimension 2). In addition, the biplot shows the projection of the original features along the components. A biplot can help us interpret the reduced dimensions of the data, and discover relationships between the principal components and original features.

Run the code cell below to produce a biplot of the reduced-dimension data.


In [14]:
# Create a biplot
vs.biplot(good_data, reduced_data, pca)


Out[14]:
<matplotlib.axes._subplots.AxesSubplot at 0x7f4bf0bbff90>

Observation

Once we have the original feature projections (in red), it is easier to interpret the relative position of each data point in the scatterplot. For instance, a point the lower right corner of the figure will likely correspond to a customer that spends a lot on 'Milk', 'Grocery' and 'Detergents_Paper', but not so much on the other product categories.

From the biplot, which of the original features are most strongly correlated with the first component? What about those that are associated with the second component? Do these observations agree with the pca_results plot you obtained earlier?

Clustering

In this section, you will choose to use either a K-Means clustering algorithm or a Gaussian Mixture Model clustering algorithm to identify the various customer segments hidden in the data. You will then recover specific data points from the clusters to understand their significance by transforming them back into their original dimension and scale.

Question 6

What are the advantages to using a K-Means clustering algorithm? What are the advantages to using a Gaussian Mixture Model clustering algorithm? Given your observations about the wholesale customer data so far, which of the two algorithms will you use and why?

Answer:

  • K-Means:
    • Fast and easy to implement.
    • Uses hard clustering to define the subgroups.
    • Warranty to find a local optimum.
  • Gaussian Mixture Model:
    • Adds more flexibility in the sense of defining the subgroups.
    • Uses a Gaussian model to predict the percentage a point has to belong to all clusters. Picks the higher one as the group where it belongs.
    • Helps uncovering some hidden variables on the data.

I will use the Gaussian Mixture model, due to the uncovered relationships between certain features. Also, after applying a log function to normalize the data points might end up in clusters they do not belong due to the underlying proximity.

Implementation: Creating Clusters

Depending on the problem, the number of clusters that you expect to be in the data may already be known. When the number of clusters is not known a priori, there is no guarantee that a given number of clusters best segments the data, since it is unclear what structure exists in the data — if any. However, we can quantify the "goodness" of a clustering by calculating each data point's silhouette coefficient. The silhouette coefficient for a data point measures how similar it is to its assigned cluster from -1 (dissimilar) to 1 (similar). Calculating the mean silhouette coefficient provides for a simple scoring method of a given clustering.

In the code block below, you will need to implement the following:

  • Fit a clustering algorithm to the reduced_data and assign it to clusterer.
  • Predict the cluster for each data point in reduced_data using clusterer.predict and assign them to preds.
  • Find the cluster centers using the algorithm's respective attribute and assign them to centers.
  • Predict the cluster for each sample data point in pca_samples and assign them sample_preds.
  • Import sklearn.metrics.silhouette_score and calculate the silhouette score of reduced_data against preds.
    • Assign the silhouette score to score and print the result.

In [15]:
from sklearn import mixture
from sklearn.metrics import silhouette_score


def get_gmm(n_comp):
    # TODO: Apply your clustering algorithm of choice to the reduced data 
    clusterer = mixture.GMM(n_components = n_comp).fit(reduced_data)

    # TODO: Predict the cluster for each data point
    preds = clusterer.predict(reduced_data)

    # TODO: Find the cluster centers
    centers = clusterer.means_

    # TODO: Predict the cluster for each transformed sample data point
    sample_preds = clusterer.predict(pca_samples)

    # TODO: Calculate the mean silhouette coefficient for the number of clusters chosen
    score = silhouette_score(reduced_data, preds)
    print 'Silhouette score for {} components is {}'.format(n_comp, score)
    return preds, centers,  sample_preds

Question 7

Report the silhouette score for several cluster numbers you tried. Of these, which number of clusters has the best silhouette score?


In [16]:
for x in range(2, 10):
    get_gmm(x)


Silhouette score for 2 components is 0.419983017307
Silhouette score for 3 components is 0.389403221495
Silhouette score for 4 components is 0.343396959874
Silhouette score for 5 components is 0.279925834327
Silhouette score for 6 components is 0.286796816629
Silhouette score for 7 components is 0.273568576769
Silhouette score for 8 components is 0.281593289467
Silhouette score for 9 components is 0.3162818087

Answer:

The scores an be seen above. The best obtained score was 2 components with a score of 0.419983017307

Cluster Visualization

Once you've chosen the optimal number of clusters for your clustering algorithm using the scoring metric above, you can now visualize the results by executing the code block below. Note that, for experimentation purposes, you are welcome to adjust the number of clusters for your clustering algorithm to see various visualizations. The final visualization provided should, however, correspond with the optimal number of clusters.


In [17]:
# Display the results of the clustering from implementation
preds, centers, sample_preds = get_gmm(2)
vs.cluster_results(reduced_data, preds, centers, pca_samples)


Silhouette score for 2 components is 0.419983017307

Implementation: Data Recovery

Each cluster present in the visualization above has a central point. These centers (or means) are not specifically data points from the data, but rather the averages of all the data points predicted in the respective clusters. For the problem of creating customer segments, a cluster's center point corresponds to the average customer of that segment. Since the data is currently reduced in dimension and scaled by a logarithm, we can recover the representative customer spending from these data points by applying the inverse transformations.

In the code block below, you will need to implement the following:

  • Apply the inverse transform to centers using pca.inverse_transform and assign the new centers to log_centers.
  • Apply the inverse function of np.log to log_centers using np.exp and assign the true centers to true_centers.

In [18]:
# TODO: Inverse transform the centers
log_centers = pca.inverse_transform(centers)

# TODO: Exponentiate the centers
true_centers = np.exp(log_centers)

# Display the true centers
segments = ['Segment {}'.format(i) for i in range(0,len(centers))]
true_centers = pd.DataFrame(np.round(true_centers), columns = data.keys())
true_centers.index = segments

print 'Centers information:'
display(true_centers)

print 'Orginal data description (without outliers):'

data_no_outliers = data.drop(data.index[outliers]).reset_index(drop = True)

display(data_no_outliers.describe())

print "Centers offset from mean"
display(true_centers - np.around(data_no_outliers.mean().values))

print "Centers offset from median"
display(true_centers - np.around(data_no_outliers.median().values))


Centers information:
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
Segment 0 8840.0 2010.0 2638.0 2021.0 340.0 727.0
Segment 1 4292.0 6321.0 9615.0 1024.0 3127.0 945.0
Orginal data description (without outliers):
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
count 427.000000 427.000000 427.000000 427.000000 427.000000 427.000000
mean 11956.725995 5522.351288 7809.142857 2882.545667 2826.170960 1429.531616
std 12586.199189 6387.365847 9349.856957 3683.549981 4636.806194 1749.102027
min 3.000000 112.000000 218.000000 33.000000 3.000000 3.000000
25% 3208.000000 1520.500000 2146.500000 770.500000 265.000000 411.500000
50% 8533.000000 3613.000000 4740.000000 1535.000000 813.000000 967.000000
75% 16718.000000 7086.000000 10502.500000 3512.500000 3935.000000 1825.500000
max 112151.000000 54259.000000 92780.000000 35009.000000 40827.000000 16523.000000
Centers offset from mean
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
Segment 0 -3117.0 -3512.0 -5171.0 -862.0 -2486.0 -703.0
Segment 1 -7665.0 799.0 1806.0 -1859.0 301.0 -485.0
Centers offset from median
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
Segment 0 307.0 -1603.0 -2102.0 486.0 -473.0 -240.0
Segment 1 -4241.0 2708.0 4875.0 -511.0 2314.0 -22.0

Question 8

Consider the total purchase cost of each product category for the representative data points above, and reference the statistical description of the dataset at the beginning of this project. What set of establishments could each of the customer segments represent?
Hint: A customer who is assigned to 'Cluster X' should best identify with the establishments represented by the feature set of 'Segment X'.

Answer:

  1. Segment 0.- The customers from this segment are primarily characterized by having an above the mean consumption of Milk, Grocery and Detergents. On the other side, it can also be observed a particularly low, close to a 30% segment, consumption of fresh and frozen products. Due to this characteristics, we can describe this segment as being a reseller like a market.
  2. Segment 1.- This particular segment has a below the mean consumption in all six different categories, which might indicate they belong to smaller establishments from the ones present in cluster 0. When comparing those values to their respective medians, we can observe two particular categories that are above the median values Fresh and Frozen products. Under this circumstances is fair to assume that those two products best represent this segment. So this customers need to restock their inventory promptly, indicating they belong to groups that produce food or fresh products like restaurants or coffee stores.

In other words, we can divide the groups into providers of goods (which buy fresh and frozen items that are placed in shelves) and those who use the supplies to create food.

Question 9

For each sample point, which customer segment from Question 8 best represents it? Are the predictions for each sample point consistent with this?

Run the code block below to find which cluster each sample point is predicted to be.


In [19]:
# Display the predictions
for i, pred in enumerate(sample_preds):
    print "Sample point", i, "predicted to be in Cluster", pred


Sample point 0 predicted to be in Cluster 1
Sample point 1 predicted to be in Cluster 1
Sample point 2 predicted to be in Cluster 0

Answer:

  1. Sample Point 0:
    • Predicted: Bakery and Pastries restaurant
    • Result: The prediction was not consisted with the customer segment. The unique characteristics of high detergent paper usage in combination with all the other products was assigned that prediction.
  2. Sample Point 1:
    • Predicted: Market Place
    • Result: Customer segment consistent with prediction.
  3. Sample Point 2:
    • Predicted: Coffee Place
    • Result: Customer segment consistent with prediction.

Conclusion

In this final section, you will investigate ways that you can make use of the clustered data. First, you will consider how the different groups of customers, the customer segments, may be affected differently by a specific delivery scheme. Next, you will consider how giving a label to each customer (which segment that customer belongs to) can provide for additional features about the customer data. Finally, you will compare the customer segments to a hidden variable present in the data, to see whether the clustering identified certain relationships.

Question 10

Companies will often run A/B tests when making small changes to their products or services to determine whether making that change will affect its customers positively or negatively. The wholesale distributor is considering changing its delivery service from currently 5 days a week to 3 days a week. However, the distributor will only make this change in delivery service for customers that react positively. How can the wholesale distributor use the customer segments to determine which customers, if any, would react positively to the change in delivery service?
Hint: Can we assume the change affects all customers equally? How can we determine which group of customers it affects the most?

Answer:

We can not assume the change will affect all customers equally. Based on the two segments we can make assumptions to be tested. Our assumption would be that the customers on segment 0, retail, will be benefited by a 3 days a week delivery based on the lack of need of daily fresh food and storage capacity to hold more product volume if needed. This will also improve their efficiency by having less product to manage and overall less work. However, segment 1 should remain with a 5 days a week model.

However, we could not assume all the customers inside each cluster have the same needs. In order to test the selected assumptions, we will select a specific numbers of customers in each cluster and put all those customers in a 3-day delivery service and evaluate their reactions. Two different non-parallel A/B tests should be created under the following principles.

  • Randon Selection: The users to be involved in the testing are going to be randomly selected from the two clusters. They should represent 20% of the population of the cluster.
  • Partition Selection: For each cluster select: 5% of the users from below the 25% threshold in the cluster, 10% from the range of 25%-75% of the cluster and the final 5% from the higher 75% of the cluster.

This will give us a better representation of the customer reaction to the new delivery service by obtaining data points from all areas of the clusters. Based on the data, the above hypothesis can be tested.

Question 11

Additional structure is derived from originally unlabeled data when using clustering techniques. Since each customer has a customer segment it best identifies with (depending on the clustering algorithm applied), we can consider 'customer segment' as an engineered feature for the data. Assume the wholesale distributor recently acquired ten new customers and each provided estimates for anticipated annual spending of each product category. Knowing these estimates, the wholesale distributor wants to classify each new customer to a customer segment to determine the most appropriate delivery service.
How can the wholesale distributor label the new customers using only their estimated product spending and the customer segment data?
Hint: A supervised learner could be used to train on the original customers. What would be the target variable?

Answer:

Since we already defined two different clusters with their separate characteristics, we can convert this problem into a supervised classification problem, in which the segment number would be the feature. The new information would be used to predict the appropriate cluster.

Since we have only two posible clusters this could be solve with a binary classifier.

Visualizing Underlying Distributions

At the beginning of this project, it was discussed that the 'Channel' and 'Region' features would be excluded from the dataset so that the customer product categories were emphasized in the analysis. By reintroducing the 'Channel' feature to the dataset, an interesting structure emerges when considering the same PCA dimensionality reduction applied earlier to the original dataset.

Run the code block below to see how each data point is labeled either 'HoReCa' (Hotel/Restaurant/Cafe) or 'Retail' the reduced space. In addition, you will find the sample points are circled in the plot, which will identify their labeling.


In [20]:
# Display the clustering results based on 'Channel' data
vs.channel_results(reduced_data, outliers, pca_samples)


Question 12

How well does the clustering algorithm and number of clusters you've chosen compare to this underlying distribution of Hotel/Restaurant/Cafe customers to Retailer customers? Are there customer segments that would be classified as purely 'Retailers' or 'Hotels/Restaurants/Cafes' by this distribution? Would you consider these classifications as consistent with your previous definition of the customer segments?

Answer: The number of clusters used on my algorithm is consistent with the above distribution. The algorithm also generalises well the overall distinction between the two clusters close to the 0.5 mark of the first dimension. We can also observe more overlapping HRC in the retailer side, possible due to the wide range this areas cover.

From the [-2] mark to the left we could consider all the data points as purely HRC and from the other side we can consider the right side of the 3 mark on the first dimension as purely retail.

I would consider this distributions as consistent with the ones obtained before due to the clear pattern that can be observed on both the previous definition and the new one. There are some overlaps, but overall we obtained a consistent pattern.

Note: Once you have completed all of the code implementations and successfully answered each question above, you may finalize your work by exporting the iPython Notebook as an HTML document. You can do this by using the menu above and navigating to
File -> Download as -> HTML (.html). Include the finished document along with this notebook as your submission.