In [ ]:

    

def reverse(string):
    return string[::-1]

string=str(input())
print(reverse(string))


    

In [ ]:

    

word=[input()]
if word[(len(word)-1)]=='s' or 'x' or 'sh' or 'ch':
    word.append('es')
elif word[(len(word)-1)]==y:
    word[(len(word)-1)]='ies'
elif word[(len(word)-1)]==f:
    word[(len(word)-1)]='ves'
else:
    word.append('s')
print(word)


    

In [ ]:

    

number=int(input('请选择三角形一边*的个数输入,number>=4'))
n=int(input('请选择三角形，1为直角三角形，2为等腰三角形，3为普通三角形'))
a='*'
if n==1:
    print(number*a)
    for i in range(1,number-1):                                       
            print(a+(number-2-i)*' '+a)
            print('\n')
    print(a)
if n==2:
    i=1
    while i<=((number+1)/2):
        print((i-1)*' '+(number-(i-1)*2)*a+(i-1)*' ')
        i+=1