#線形補間 課題1 ##鈴木大志
In [1]:
println(readall("lin_interp2.jl"))
In [2]:
include("lin_interp2.jl")
Out[2]:
#sin(x)の線形補間と残差
In [3]:
using PyPlot
grid = [-8, -4, -2, 0, 2, 4, 6, 8]
vals = sin(grid)
points = lin_interp2(grid, vals)
x = [-10:0.01:10]
residual(x) = sin(x) - points(x)
plot(points(x))
plot(sin(x))
plot(residual(x))
Out[3]:
In [ ]: