Euler Problem 20

n! means n × (n − 1) × ... × 3 × 2 × 1

For example, 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800, and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.

Find the sum of the digits in the number 100!


In [1]:
from functools import reduce
print(sum(map(int,list(str(reduce(lambda x,y:x*y,range(1, 101)))))))


648

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