In [66]:
from math import pi
import pint
u = pint.UnitRegistry()
In [67]:
L = 1800*u.mm
Le = 0.5*L
Le = 1800*u.mm
b = 12*u.mm
d = 20*u.mm
In [68]:
I = (1/12)*b*d**3
I
Out[68]:
In [69]:
E = 15e6*u.psi
In [70]:
E.ito(u.MPa)
E
Out[70]:
In [71]:
Pcr = ((pi**2)*E*I)/(Le**2)
Pcr.to(u.N)
Out[71]:
In [72]:
Pallow=Pcr/5
In [73]:
Pallow
Out[73]:
In [75]:
I.to(u.inch**4)
Out[75]:
In [76]:
L.to(u.inch)
Out[76]:
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