Multiclass Support Vector Machine exercise

Complete and hand in this completed worksheet (including its outputs and any supporting code outside of the worksheet) with your assignment submission. For more details see the assignments page on the course website.

In this exercise you will:

  • implement a fully-vectorized loss function for the SVM
  • implement the fully-vectorized expression for its analytic gradient
  • check your implementation using numerical gradient
  • use a validation set to tune the learning rate and regularization strength
  • optimize the loss function with SGD
  • visualize the final learned weights

In [1]:
# Run some setup code for this notebook.

import random
import numpy as np
from cs231n.data_utils import load_CIFAR10
import matplotlib.pyplot as plt

from __future__ import print_function

# This is a bit of magic to make matplotlib figures appear inline in the
# notebook rather than in a new window.
%matplotlib inline
plt.rcParams['figure.figsize'] = (10.0, 8.0) # set default size of plots
plt.rcParams['image.interpolation'] = 'nearest'
plt.rcParams['image.cmap'] = 'gray'

# Some more magic so that the notebook will reload external python modules;
# see http://stackoverflow.com/questions/1907993/autoreload-of-modules-in-ipython
%load_ext autoreload
%autoreload 2

CIFAR-10 Data Loading and Preprocessing


In [2]:
# Load the raw CIFAR-10 data.
cifar10_dir = 'cs231n/datasets/cifar-10-batches-py'
X_train, y_train, X_test, y_test = load_CIFAR10(cifar10_dir)

# As a sanity check, we print out the size of the training and test data.
print('Training data shape: ', X_train.shape)
print('Training labels shape: ', y_train.shape)
print('Test data shape: ', X_test.shape)
print('Test labels shape: ', y_test.shape)


Training data shape:  (50000, 32, 32, 3)
Training labels shape:  (50000,)
Test data shape:  (10000, 32, 32, 3)
Test labels shape:  (10000,)

In [3]:
# Visualize some examples from the dataset.
# We show a few examples of training images from each class.
classes = ['plane', 'car', 'bird', 'cat', 'deer', 'dog', 'frog', 'horse', 'ship', 'truck']
num_classes = len(classes)
samples_per_class = 7
for y, cls in enumerate(classes):
    idxs = np.flatnonzero(y_train == y)
    idxs = np.random.choice(idxs, samples_per_class, replace=False)
    for i, idx in enumerate(idxs):
        plt_idx = i * num_classes + y + 1
        plt.subplot(samples_per_class, num_classes, plt_idx)
        plt.imshow(X_train[idx].astype('uint8'))
        plt.axis('off')
        if i == 0:
            plt.title(cls)
plt.show()



In [4]:
# Split the data into train, val, and test sets. In addition we will
# create a small development set as a subset of the training data;
# we can use this for development so our code runs faster.
num_training = 49000
num_validation = 1000
num_test = 1000
num_dev = 500

# Our validation set will be num_validation points from the original
# training set.
mask = range(num_training, num_training + num_validation)
X_val = X_train[mask]
y_val = y_train[mask]

# Our training set will be the first num_train points from the original
# training set.
mask = range(num_training)
X_train = X_train[mask]
y_train = y_train[mask]

# We will also make a development set, which is a small subset of
# the training set.
mask = np.random.choice(num_training, num_dev, replace=False)
X_dev = X_train[mask]
y_dev = y_train[mask]

# We use the first num_test points of the original test set as our
# test set.
mask = range(num_test)
X_test = X_test[mask]
y_test = y_test[mask]

print('Train data shape: ', X_train.shape)
print('Train labels shape: ', y_train.shape)
print('Validation data shape: ', X_val.shape)
print('Validation labels shape: ', y_val.shape)
print('Test data shape: ', X_test.shape)
print('Test labels shape: ', y_test.shape)


Train data shape:  (49000, 32, 32, 3)
Train labels shape:  (49000,)
Validation data shape:  (1000, 32, 32, 3)
Validation labels shape:  (1000,)
Test data shape:  (1000, 32, 32, 3)
Test labels shape:  (1000,)

In [5]:
# Preprocessing: reshape the image data into rows
X_train = np.reshape(X_train, (X_train.shape[0], -1))
X_val = np.reshape(X_val, (X_val.shape[0], -1))
X_test = np.reshape(X_test, (X_test.shape[0], -1))
X_dev = np.reshape(X_dev, (X_dev.shape[0], -1))

# As a sanity check, print out the shapes of the data
print('Training data shape: ', X_train.shape)
print('Validation data shape: ', X_val.shape)
print('Test data shape: ', X_test.shape)
print('dev data shape: ', X_dev.shape)


Training data shape:  (49000, 3072)
Validation data shape:  (1000, 3072)
Test data shape:  (1000, 3072)
dev data shape:  (500, 3072)

In [6]:
# Preprocessing: subtract the mean image
# first: compute the image mean based on the training data
mean_image = np.mean(X_train, axis=0)
print(mean_image[:10]) # print a few of the elements
plt.figure(figsize=(4,4))
plt.imshow(mean_image.reshape((32,32,3)).astype('uint8')) # visualize the mean image
plt.show()


[ 130.64189796  135.98173469  132.47391837  130.05569388  135.34804082
  131.75402041  130.96055102  136.14328571  132.47636735  131.48467347]

In [7]:
# second: subtract the mean image from train and test data
X_train -= mean_image
X_val -= mean_image
X_test -= mean_image
X_dev -= mean_image

In [8]:
# third: append the bias dimension of ones (i.e. bias trick) so that our SVM
# only has to worry about optimizing a single weight matrix W.
X_train = np.hstack([X_train, np.ones((X_train.shape[0], 1))])
X_val = np.hstack([X_val, np.ones((X_val.shape[0], 1))])
X_test = np.hstack([X_test, np.ones((X_test.shape[0], 1))])
X_dev = np.hstack([X_dev, np.ones((X_dev.shape[0], 1))])

print(X_train.shape, X_val.shape, X_test.shape, X_dev.shape)


(49000, 3073) (1000, 3073) (1000, 3073) (500, 3073)

SVM Classifier

Your code for this section will all be written inside cs231n/classifiers/linear_svm.py.

As you can see, we have prefilled the function compute_loss_naive which uses for loops to evaluate the multiclass SVM loss function.


In [9]:
# Evaluate the naive implementation of the loss we provided for you:
from cs231n.classifiers.linear_svm import svm_loss_naive
import time

# generate a random SVM weight matrix of ·small numbers
W = np.random.randn(3073, 10) * 0.0001 

loss, grad = svm_loss_naive(W, X_dev, y_dev, 0.000005)
print('loss: %f' % (loss, ))


loss: 8.754665

The grad returned from the function above is right now all zero. Derive and implement the gradient for the SVM cost function and implement it inline inside the function svm_loss_naive. You will find it helpful to interleave your new code inside the existing function.

To check that you have correctly implemented the gradient correctly, you can numerically estimate the gradient of the loss function and compare the numeric estimate to the gradient that you computed. We have provided code that does this for you:


In [10]:
# Once you've implemented the gradient, recompute it with the code below
# and gradient check it with the function we provided for you

# Compute the loss and its gradient at W.
loss, grad = svm_loss_naive(W, X_dev, y_dev, 0.0)

# Numerically compute the gradient along several randomly chosen dimensions, and
# compare them with your analytically computed gradient. The numbers should match
# almost exactly along all dimensions.
from cs231n.gradient_check import grad_check_sparse
f = lambda w: svm_loss_naive(w, X_dev, y_dev, 0.0)[0]
grad_numerical = grad_check_sparse(f, W, grad)

# do the gradient check once again with regularization turned on
# you didn't forget the regularization gradient did you?
loss, grad = svm_loss_naive(W, X_dev, y_dev, 5e1)
f = lambda w: svm_loss_naive(w, X_dev, y_dev, 5e1)[0]
grad_numerical = grad_check_sparse(f, W, grad)


numerical: 13.953415 analytic: 13.953415, relative error: 4.296395e-12
numerical: 0.956570 analytic: 0.956570, relative error: 2.905704e-10
numerical: 9.918138 analytic: 9.918138, relative error: 2.317560e-11
numerical: 5.979742 analytic: 5.979742, relative error: 5.880210e-11
numerical: -2.419887 analytic: -2.433499, relative error: 2.804714e-03
numerical: 24.473221 analytic: 24.505542, relative error: 6.599010e-04
numerical: 3.637503 analytic: 3.637503, relative error: 2.230284e-11
numerical: 18.037754 analytic: 17.949580, relative error: 2.450146e-03
numerical: -1.480424 analytic: -1.476322, relative error: 1.387071e-03
numerical: -3.190929 analytic: -3.190929, relative error: 1.212178e-11
numerical: 0.928721 analytic: 0.928721, relative error: 2.051074e-10
numerical: -3.670114 analytic: -3.670114, relative error: 8.995293e-11
numerical: -8.482064 analytic: -8.482064, relative error: 2.791605e-11
numerical: 24.325363 analytic: 24.325363, relative error: 1.252304e-12
numerical: -26.430498 analytic: -26.430498, relative error: 3.551975e-12
numerical: 11.736548 analytic: 11.734753, relative error: 7.649435e-05
numerical: 10.709269 analytic: 10.709269, relative error: 2.631609e-11
numerical: -4.199496 analytic: -4.199496, relative error: 6.106367e-11
numerical: 13.665580 analytic: 13.665580, relative error: 5.348992e-12
numerical: -12.718056 analytic: -12.718056, relative error: 1.819661e-11

Inline Question 1:

It is possible that once in a while a dimension in the gradcheck will not match exactly. What could such a discrepancy be caused by? Is it a reason for concern? What is a simple example in one dimension where a gradient check could fail? Hint: the SVM loss function is not strictly speaking differentiable

Your Answer: fill this in.


In [11]:
# Next implement the function svm_loss_vectorized; for now only compute the loss;
# we will implement the gradient in a moment.
tic = time.time()
loss_naive, grad_naive = svm_loss_naive(W, X_dev, y_dev, 0.000005)
toc = time.time()
print('Naive loss: %e computed in %fs' % (loss_naive, toc - tic))

from cs231n.classifiers.linear_svm import svm_loss_vectorized
tic = time.time()
loss_vectorized, _ = svm_loss_vectorized(W, X_dev, y_dev, 0.000005)
toc = time.time()
print('Vectorized loss: %e computed in %fs' % (loss_vectorized, toc - tic))

# The losses should match but your vectorized implementation should be much faster.
print('difference: %f' % (loss_naive - loss_vectorized))


Naive loss: 8.754665e+00 computed in 0.076010s
Vectorized loss: 8.754665e+00 computed in 0.011030s
difference: 0.000000

In [12]:
# Complete the implementation of svm_loss_vectorized, and compute the gradient
# of the loss function in a vectorized way.

# The naive implementation and the vectorized implementation should match, but
# the vectorized version should still be much faster.
tic = time.time()
_, grad_naive = svm_loss_naive(W, X_dev, y_dev, 0.000005)
toc = time.time()
print('Naive loss and gradient: computed in %fs' % (toc - tic))

tic = time.time()
_, grad_vectorized = svm_loss_vectorized(W, X_dev, y_dev, 0.000005)
toc = time.time()
print('Vectorized loss and gradient: computed in %fs' % (toc - tic))

# The loss is a single number, so it is easy to compare the values computed
# by the two implementations. The gradient on the other hand is a matrix, so
# we use the Frobenius norm to compare them.
difference = np.linalg.norm(grad_naive - grad_vectorized, ord='fro')
print('difference: %f' % difference)


Naive loss and gradient: computed in 0.074226s
Vectorized loss and gradient: computed in 0.011028s
difference: 0.000000

Stochastic Gradient Descent

We now have vectorized and efficient expressions for the loss, the gradient and our gradient matches the numerical gradient. We are therefore ready to do SGD to minimize the loss.


In [13]:
# In the file linear_classifier.py, implement SGD in the function
# LinearClassifier.train() and then run it with the code below.
from cs231n.classifiers import LinearSVM
svm = LinearSVM()
tic = time.time()
loss_hist = svm.train(X_train, y_train, learning_rate=1e-7, reg=2.5e4,
                      num_iters=1500, verbose=True)
toc = time.time()
print('That took %fs' % (toc - tic))


iteration 0 / 1500: loss 404.256425
iteration 100 / 1500: loss 238.084225
iteration 200 / 1500: loss 146.062558
iteration 300 / 1500: loss 88.473642
iteration 400 / 1500: loss 55.740994
iteration 500 / 1500: loss 35.805175
iteration 600 / 1500: loss 23.660021
iteration 700 / 1500: loss 15.954448
iteration 800 / 1500: loss 11.947188
iteration 900 / 1500: loss 9.329015
iteration 1000 / 1500: loss 8.047547
iteration 1100 / 1500: loss 6.436429
iteration 1200 / 1500: loss 5.805725
iteration 1300 / 1500: loss 5.732202
iteration 1400 / 1500: loss 5.871771
That took 7.935123s

In [14]:
# A useful debugging strategy is to plot the loss as a function of
# iteration number:
plt.plot(loss_hist)
plt.xlabel('Iteration number')
plt.ylabel('Loss value')
plt.show()



In [15]:
# Write the LinearSVM.predict function and evaluate the performance on both the
# training and validation set
y_train_pred = svm.predict(X_train)
print('training accuracy: %f' % (np.mean(y_train == y_train_pred), ))
y_val_pred = svm.predict(X_val)
print('validation accuracy: %f' % (np.mean(y_val == y_val_pred), ))


training accuracy: 0.377122
validation accuracy: 0.392000

In [16]:
# Use the validation set to tune hyperparameters (regularization strength and
# learning rate). You should experiment with different ranges for the learning
# rates and regularization strengths; if you are careful you should be able to
# get a classification accuracy of about 0.4 on the validation set.
learning_rates = [1e-7, 5e-5]
regularization_strengths = [2.5e4, 5e4]

# results is dictionary mapping tuples of the form
# (learning_rate, regularization_strength) to tuples of the form
# (training_accuracy, validation_accuracy). The accuracy is simply the fraction
# of data points that are correctly classified.
results = {}
best_val = -1   # The highest validation accuracy that we have seen so far.
best_svm = None # The LinearSVM object that achieved the highest validation rate.

################################################################################
# TODO:                                                                        #
# Write code that chooses the best hyperparameters by tuning on the validation #
# set. For each combination of hyperparameters, train a linear SVM on the      #
# training set, compute its accuracy on the training and validation sets, and  #
# store these numbers in the results dictionary. In addition, store the best   #
# validation accuracy in best_val and the LinearSVM object that achieves this  #
# accuracy in best_svm.                                                        #
#                                                                              #
# Hint: You should use a small value for num_iters as you develop your         #
# validation code so that the SVMs don't take much time to train; once you are #
# confident that your validation code works, you should rerun the validation   #
# code with a larger value for num_iters.                                      #
################################################################################

for lr in learning_rates:
    for rs in regularization_strengths:   
        svm = LinearSVM()
        loss_hist = svm.train(X_train, y_train, learning_rate=1e-7, reg=2.5e4,
                              num_iters=1500, verbose=True)
        ytrainPred = svm.predict(X_train)
        trAC = np.mean(y_train == ytrainPred)
        yvalPred = svm.predict(X_val)
        valAC = np.mean(y_val == yvalPred)
        
        results[(lr, rs)] = (trAC, valAC)
        
        if valAC > best_val:
            best_val = valAC
            best_svm = svm

################################################################################
#                              END OF YOUR CODE                                #
################################################################################
    
# Print out results.
for lr, reg in sorted(results):
    train_accuracy, val_accuracy = results[(lr, reg)]
    print('lr %e reg %e train accuracy: %f val accuracy: %f' % (
                lr, reg, train_accuracy, val_accuracy))
    
print('best validation accuracy achieved during cross-validation: %f' % best_val)


iteration 0 / 1500: loss 408.513695
iteration 100 / 1500: loss 240.022459
iteration 200 / 1500: loss 147.643209
iteration 300 / 1500: loss 89.741668
iteration 400 / 1500: loss 55.950658
iteration 500 / 1500: loss 36.012489
iteration 600 / 1500: loss 23.875743
iteration 700 / 1500: loss 16.413440
iteration 800 / 1500: loss 12.284307
iteration 900 / 1500: loss 9.463263
iteration 1000 / 1500: loss 8.024153
iteration 1100 / 1500: loss 6.391747
iteration 1200 / 1500: loss 5.653302
iteration 1300 / 1500: loss 5.079858
iteration 1400 / 1500: loss 5.631535
iteration 0 / 1500: loss 407.017532
iteration 100 / 1500: loss 238.636103
iteration 200 / 1500: loss 146.493519
iteration 300 / 1500: loss 89.820295
iteration 400 / 1500: loss 55.813348
iteration 500 / 1500: loss 35.736827
iteration 600 / 1500: loss 23.821779
iteration 700 / 1500: loss 16.804752
iteration 800 / 1500: loss 11.603095
iteration 900 / 1500: loss 8.793803
iteration 1000 / 1500: loss 7.038712
iteration 1100 / 1500: loss 7.343460
iteration 1200 / 1500: loss 6.219120
iteration 1300 / 1500: loss 5.356864
iteration 1400 / 1500: loss 5.419213
iteration 0 / 1500: loss 409.520652
iteration 100 / 1500: loss 242.814421
iteration 200 / 1500: loss 146.995744
iteration 300 / 1500: loss 91.430320
iteration 400 / 1500: loss 56.374845
iteration 500 / 1500: loss 36.479560
iteration 600 / 1500: loss 23.960733
iteration 700 / 1500: loss 16.256479
iteration 800 / 1500: loss 11.335890
iteration 900 / 1500: loss 8.861341
iteration 1000 / 1500: loss 7.592117
iteration 1100 / 1500: loss 6.095502
iteration 1200 / 1500: loss 6.089136
iteration 1300 / 1500: loss 5.877095
iteration 1400 / 1500: loss 5.384195
iteration 0 / 1500: loss 416.709675
iteration 100 / 1500: loss 245.207000
iteration 200 / 1500: loss 149.195283
iteration 300 / 1500: loss 91.770853
iteration 400 / 1500: loss 57.311490
iteration 500 / 1500: loss 36.243965
iteration 600 / 1500: loss 24.359120
iteration 700 / 1500: loss 16.239991
iteration 800 / 1500: loss 11.930230
iteration 900 / 1500: loss 9.590687
iteration 1000 / 1500: loss 7.310338
iteration 1100 / 1500: loss 6.292660
iteration 1200 / 1500: loss 6.097247
iteration 1300 / 1500: loss 5.385333
iteration 1400 / 1500: loss 5.655474
lr 1.000000e-07 reg 2.500000e+04 train accuracy: 0.373163 val accuracy: 0.380000
lr 1.000000e-07 reg 5.000000e+04 train accuracy: 0.382306 val accuracy: 0.385000
lr 5.000000e-05 reg 2.500000e+04 train accuracy: 0.377469 val accuracy: 0.372000
lr 5.000000e-05 reg 5.000000e+04 train accuracy: 0.380286 val accuracy: 0.388000
best validation accuracy achieved during cross-validation: 0.388000

In [17]:
# Visualize the cross-validation results
import math
x_scatter = [math.log10(x[0]) for x in results]
y_scatter = [math.log10(x[1]) for x in results]

# plot training accuracy
marker_size = 100
colors = [results[x][0] for x in results]
plt.subplot(2, 1, 1)
plt.scatter(x_scatter, y_scatter, marker_size, c=colors)
plt.colorbar()
plt.xlabel('log learning rate')
plt.ylabel('log regularization strength')
plt.title('CIFAR-10 training accuracy')

# plot validation accuracy
colors = [results[x][1] for x in results] # default size of markers is 20
plt.subplot(2, 1, 2)
plt.scatter(x_scatter, y_scatter, marker_size, c=colors)
plt.colorbar()
plt.xlabel('log learning rate')
plt.ylabel('log regularization strength')
plt.title('CIFAR-10 validation accuracy')
plt.show()



In [18]:
# Evaluate the best svm on test set
y_test_pred = best_svm.predict(X_test)
test_accuracy = np.mean(y_test == y_test_pred)
print('linear SVM on raw pixels final test set accuracy: %f' % test_accuracy)


linear SVM on raw pixels final test set accuracy: 0.381000

In [19]:
# Visualize the learned weights for each class.
# Depending on your choice of learning rate and regularization strength, these may
# or may not be nice to look at.
w = best_svm.W[:-1,:] # strip out the bias
w = w.reshape(32, 32, 3, 10)
w_min, w_max = np.min(w), np.max(w)
classes = ['plane', 'car', 'bird', 'cat', 'deer', 'dog', 'frog', 'horse', 'ship', 'truck']
for i in range(10):
    plt.subplot(2, 5, i + 1)
      
    # Rescale the weights to be between 0 and 255
    wimg = 255.0 * (w[:, :, :, i].squeeze() - w_min) / (w_max - w_min)
    plt.imshow(wimg.astype('uint8'))
    plt.axis('off')
    plt.title(classes[i])


Inline question 2:

Describe what your visualized SVM weights look like, and offer a brief explanation for why they look they way that they do.

Your answer: fill this in